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3 years ago

What is the answer .

Mathematics

1 answer:

aivan3 [116]3 years ago

6 0

Answer: B

Step-by-step explanation: I first simplified the expression which gave me 6^6 x 1/6^8 then, I reduced the expression with 6^6 which is now 1/6^2. After, I evaluated the power which is now 1/26. So the answer is B.

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The table gives an inequality and a number to multiply both sides of the inequality by. Identify the new, true inequality.

EastWind [94]

Answer:

its B

Step-by-step explanation:

4 0

2 years ago

Solve -3(x+5) = -9 solve

Bumek [7]

-3(x + 5) = -9
-3x + -15 = -9
-3x - 15 = -9
-3x - 15 + 15 = -9 + 15 (we added 15 to both sides of the equation because now, the 15 on the left side cancels out).
-3x = 6
-3x/-3 = 6/-3
X = -2
So, in conclusion, X is equal to -2.

5 0

2 years ago

Read 2 more answers

Find the distance between each set of points. Round to the nearest tenth, when necessary. (-3, 2) and (1, -6)

vovangra [49]

Answer:

<h2>The answer is 8.9 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3, 2) and (1, -6)

The distance between them is

$d = \sqrt{ ({ - 3 - 1})^{2} + ({2 + 6})^{2} } \\ = \sqrt{ ({ - 4})^{2} + {8}^{2} } \\ = \sqrt{16 + 64} \\ = \sqrt{80} \: \: \: \: \: \: \: \: \: \: \\ = 4 \sqrt{5} \: \: \: \: \: \: \: \: \: \: \\ = 8.9442719...$

We have the final answer as

8.9 units to the nearest tenth

Hope this helps you

6 0

2 years ago

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – x – 7 = 0

Tanzania [10]

2x-x-7=0

3x-7=0

add 7 to 7 and 0, so then we cross out 7-7, and then

3x=7, bc u change the subtraction to addition, sr if thst doesn't make sense but 3x=7 is the answer

8 0

3 years ago

Read 2 more answers

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$