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3 years ago

Find the volume of a cylinder with a height of 8cm and a radius of 3cm

Mathematics

2 answers:

just olya [345]3 years ago

8 0

Answer:

Step-by-step explanation:

V = (pie) * 3 *3 * 8

V = 72 pie cm (3)

Its on a p e x

kolezko [41]3 years ago

3 0

Answer:

V≈226.19cm³

Step-by-step explanation:

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How many sqft is in a rectangle of 360 by 190 feet

monitta

Answer: 68400

Explanation: The question is asking for area so you do base times height. In this case you multiply 360 times 190.

4 0

3 years ago

A. X=3 m B. X=5 m C. X=6 m D. X=9 m

enyata [817]

Answer:

ok so we can divide 15 by 5 to get 3

so we know the building is 3 times bigger

so we multiply 3 by 3 to get 9

so the answer is D

8 0

3 years ago

Read 2 more answers

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let x be the width and y the length of the rectangular field.

Let C the total cost of the rectangular field.

The side made of heavy duty material of length of x costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are x, y, y. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

3 years ago

Zoey read a novel in 30 days she made it a habit to read 13 pages everyday for the first 20 days. if in the last 10 days she rea

Elden [556K]

Answer:320

Explanation:

20 days times 13 pages= 260pages
10 days times 6 pages = 60pages

Total for the 30 days:
260+60= 320 pages total

7 0

2 years ago

Read 2 more answers

To complete a task in 15 days a company needs 4 people each working for 8 hours per day. the company decides to have 5 people ea

Lilit [14]

It would take 16 days
explanation
if it takes 15 for 4 people to work 8 hours to complete the task, it would be a total of 480 hours. I multiplied 15x4x8. i multiplied 5x6 to get 30. I have to find the third value so i divided 30 from 480 to get 16.

3 0

3 years ago