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2 years ago

Use the properties of addition to simplify 2d + 2 - 7f+ 4d - f.

Mathematics

2 answers:

Rudik [331]2 years ago

8 0

6d - 8f + 2

hope this helps

lesya692 [45]2 years ago

7 0

Answer:

6d - 8f + 2

Step-by-step explanation:

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Find sin, where the angle is shown Give the exact value, not a decimal approximation

olga_2 [115]

Answer:

sinΘ = $\frac{24}{25}$

Step-by-step explanation:

sinΘ = $\frac{opposite}{hypotenuse}$

The opposite is 24, but we require the hypotenuse h

Using Pythagoras' identity

h² = 7² + 24² = 49 + 576 = 625 ( take square root of both sides )

h = $\sqrt{625}$ = 25

Thus

sinΘ = $\frac{24}{25}$

6 0

2 years ago

Reply with quote {(-1,3),(0,5),(1,7),(2,9)} , identify the domain and range

Contact [7]

The domain is -1,0,1,2. The range is 3,5,7,9.

4 0

2 years ago

Solve: i)x+y=5 ii)x-y=3 iii)2x+y=7 iv)3x-2y=0

Ulleksa [173]

Answer:

I) X+Y

when X=0

0+y=5

Y=5

When Y=0

X+0=5

X=5

(X,y)=(5,5)

(ii) X-Y=3

When X=0

0-Y=3

Y=-3

When Y=0

X-0=3

X=3

(X,Y)=(3,3(

(III) 2x+Y=7

when X=0

0+Y=7

Y=7

when Y=0

2x+0=7

2x=7

X=7/2 or 3.5

(X,Y)=(3.5,7)

(Iv)

3X-2Y=0

when X=0

0-2Y=0

-2Y=0

Y=0

When Y=0

3x-0=0

3X=0

X=0

(X,Y)=(0,0)

5 0

1 year ago

Gina takes out a loan totaling $5000. The loan has a 5% interest rate that is compounded monthly. What is the total due after 48

dimaraw [331]

Using the formula A=P(1+i/100)^n
where A is the investment/loan after n years, P is the original investment/loan and i% is the interest per annum.

A=5000(1+0.05)^48
A=52006.35

4 0

2 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

shusha [124]

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int_{-\infty}^{0}1000e^xdx$

$I=1000=\int_{-\infty}^{0}e^xdx$

integration of $e^x$ is $e^x$

$I=1000\times \left [ e^x\right ]^{0}_{-\infty}$

$I=1000\times I=\left [ e^0-e^{-\infty}\right ]$

$I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]$

$I=1000\times 1=1000$

so the integration converges to 1000 units

6 0

2 years ago