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Naily [24]
3 years ago
9

Solve x and y. show all work

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

Solution given:

y+135°=180°[sum of opposite angle of a cyclic quadrilateral is supplementary]

y=180°-135°

y=25°

again

2x-1+3x+1=180°[sum of opposite angle of a cyclic quadrilateral is supplementary]

5x=180

x=180/5.x=36

x=36°,y=25°

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Draw a line that connects each table to the correct graph
stealth61 [152]

Answer:

For number 1, you draw a line to the middle graph

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For number 3, you draw a line to the top graph.

Step-by-step explanation:

To figure out where the graph goes, you only need to know if the point is on the graph. For the top graph, you know that the point 2,2 is on the graph so that means one part of the graph has to be 2 and 2. The x has to equal to and the y is equal 2. Therefore, you have to draw it to the bottom graph.

If this has helped you, please mark this answer as brainliest

4 0
3 years ago
What properties does a square have in common with a quadrilateral?
Mashcka [7]
Hey there 

<span>Quadrilateral "four sided shape"</span>
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6 0
3 years ago
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Neko [114]
31-(-5) = 155
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4 0
3 years ago
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The 1996 gss asked, "if the husband in a family wants children, but the wife decides that she does not want any children, is it
zzz [600]
The confidence interval would be
0.80\pm0.03.

We use the formula
p\pm z*\sigma_p, where

\sigma_p=\sqrt{\frac{p(1-p)}{N}}, with p being the sample proportion and N being the sample size.

First we find the z-score associated with this level of confidence:
Convert 95% to a decimal:  95/100 = 0.95
Subtract from 1:  1-0.95 = 0.05
Divide by 2:  0.05/2 = 0.025
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Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 1.96.

Since 578/720 said yes, this gives us p=0.80:
\sigma_p=\sqrt{\frac{0.80(1-0.80)}{720}}=\sqrt{\frac{0.8(0.2)}{720}=0.015

This gives us
0.80\pm1.96(0.015)=0.80\pm 0.03
5 0
3 years ago
(7q3r2 + 5qr2 + 23q) + (−5qr2 − qr² − 11q − 4q3r2) adding polynomials horizontally
zysi [14]

You can remove the  parentheses:-

= 7q^3r^2 + 5qr^2 + 23q + −5qr^2 − qr^2 − 11q − 4q^3r^2  ( because there is + outside)

Bring like terms together

= 7q^3r^2 − 4q^3r^2  + 5qr^2  − 5qr^2 − qr^2 + 23q − 11q

= 3q^3r^2 - qr^2 + 12q   answer

5 0
3 years ago
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