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Solnce55 [7]
3 years ago
13

Which equation is quadratic in form?

Mathematics
2 answers:
just olya [345]3 years ago
5 0

Answer:

2

Step-by-step explanation:

i think

Karolina [17]3 years ago
3 0
I think it’s 2 to be honest it only makes since
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If Dante spins the spinner below 75 times, how many times should he expect it to land on "U"?​
Fed [463]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete; So, I will solve making assumptions

Spinner = 10\ segments

U = 1

n=75

Required

Number of times to land on U

First, calculate the theoretical probability of U

Pr(U) = \frac{U}{Spinner}

Pr(U) = \frac{1}{10}

The expected number (E) of time to land on U is then calculated as:

E = Pr(U) * n

E = \frac{1}{10} * 75

E = 0.10 * 75

E = 7.5

Approximate

E = 8

<em>8 times</em>

<em></em>

<em>Follow the above steps, and you will arrive at your answer</em>

3 0
2 years ago
Is this answer correct?
34kurt

Answer:

Step-by-step explanation:

yes the answer is correct

7 0
3 years ago
Read 2 more answers
I need help please?!!
Sveta_85 [38]

Answer:

72

Step-by-step explanation:

8 0
3 years ago
If the discount is 27%, then what percentage of the original price do you pay? Please give an explanation as well if you can! Th
lina2011 [118]
100-27=73
Therefore you paid 73% of the original price. That’s the remaining percentage
7 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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