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chubhunter [2.5K]
3 years ago
11

Kristine has a weekend job advertising an upcoming play. She has two options for being paid. Option A is an hourly wage of ​$7.0

0. Option B is a 5% commission on all money made at the play. She plans to work 8 hours each day on Saturday and Sunday. Kristine estimates the play will make about ​$2,100 this weekend. Which option gives Kristine more earnings this​ weekend?
(which one is the answer)

A. Both options give Kristine the same amount of earnings.
B. Option B gives Kristine more earnings this weekend.
C. Option A gives Kristine more earnings this weekend.
do your best and show your work and the one with the right answer will get a brainliest and im not joking
Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Answer:

The answer is Option A

Step-by-step explanation

If she were to do 5% she would get 105 dollars.

If she were to do $ 7.00 dollars2 days a week hourly she would get 112 dollars. This means option a is the best choice.

Zepler [3.9K]3 years ago
7 0

Answer:

Option B

Step-by-step explanation:

Option A: 7h=56 h=8 she is making $56

Option B .05 x 56=2.8. 56 + 2.8 = 58.8

They can't be the same so option C is out

She is making 2.80 with option B hoped that helped

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Greeley [361]

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Step-by-step explanation:

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(5y 3 + 20y 2 – 12)(2y3 - 15y2 + 4y + 16)
Alex

Answer:

225y5-192

Step-by-step explanation:

8 0
3 years ago
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Ierofanga [76]

Answer:

A

Step-by-step explanation:

Sum the product of the components in the first row of A with the corresponding components of the first column in B

Repeat this with the components in the second row of A with the corresponding components of the second column in B, that is

AB

= \left[\begin{array}{ccc}2&1\\3&4\\\end{array}\right] \left[\begin{array}{ccc}3&1\\5&2\\\end{array}\right]

= \left[\begin{array}{ccc}2(3)+1(5)&2(1)+1(2)\\3(3)+4(5)&3(1)+4(2)\\\end{array}\right]

= \left[\begin{array}{ccc}6+5&2+2\\9+20&3+8\\\end{array}\right]

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6 0
3 years ago
A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t
Vikki [24]

Answer:

The value is   P(X \ge 9) = 0.9138

Step-by-step explanation:

From the question we are told that

  The probability of passing the test is  p =  0.95

  The sample size is  n  =  10  

Generally the distribution of the comprehensive testing of equipment  follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators

  Generally the probability that at least 9 pass the test  is mathematically represented as

    P(X \ge 9) =  P(X = 9 ) + P(X = 10 )

=> P(X \ge 9) =  [^{10}C_9 *  (0.95)^9 *  (1- 0.95)^{10-9}] + [^{10}C_{10} *  (0.95)^{10} *  (1- 0.95)^{10-10}]

=> P(X \ge 9) =  [0.3151] + [0.5987]

=> P(X \ge 9) = 0.9138

7 0
3 years ago
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