Can someone please help on question 4? I will give you brainliest

Mathematics

2 answers:

Leona [35]3 years ago

8 0

Answer:

The area of the right circular cone is:

$A = 642$ cm²

Step-by-step explanation:

Given

Height of right cone = h = 13 cm

Base diameter = 17 cm

so radis = r = 17/2 = 8.5 cm

Using the formula to determine the right circular cone

$A\:=\:\pi r\:\left(r+\sqrt{h^2+r^2}\right)$

substituting h = 13, and r = 8.5

$A\:=\:\pi \left(8.5\right)\:\left(8.5+\sqrt{\left(13\right)^2+\left(8.5\right)^2}\right)$

$A=8.5\pi \left(8.5+\sqrt{241.25}\right)$

$A = 642$ cm²

Therefore, the area of the right circular cone is:

$A = 642$ cm²

Julli [10]3 years ago

5 0

Answer:

answer a

Step-by-step explanation:

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$