Answer: 87, 88, 89, 91, 92, 93, 94, 95, 96, 97, 98
Step-by-step explanation:
You basically try a whole bunch of numbers by taking those two numbers and another then adding them and dividing them by 3.
X^3 + 10x^2 + 24x
divide by x
x(x^2 + 10x + 24)
factor it
x(x+4)(x + 6)
now solve for x
the answer is -6,0,-4
Answer:
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
Step-by-step explanation:
1. Let's check all the information provided to answer the question:
Time of Thomas flight delay = 1 5/6 hours
Time of normal flight = x hours
2. How long did the trip finally take?
For calculating how long the trip finally took, we need to do the following sum:
Time of normal flight + Time of delay
Like we don't know the time of the normal flight, we will define it as x, then:
x + 1 5/6 hours
x + 1 hour and 50 minutes ⇒ 5/6 of an hour = 5/6 * 60 minutes = 50 minutes
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
Answer:
- hits the ground at x = -0.732, and x = 2.732
- only the positive solution is reasonable
Step-by-step explanation:
The acorn will hit the ground where the value of x is such that y=0. We can find these values of x by solving the quadratic using any of several means.
__
<h3>graphing</h3>
The attachment shows a graphing calculator solution to the equation
-3x^2 + 6x + 6 = 0
The values of x are -0.732 and 2.732. The negative value is the point where the acorn would have originated from if its parabolic path were extrapolated backward in time. Only the positive horizontal distance is a reasonable solution.
__
<h3>completing the square</h3>
We can also solve the equation algebraically. One of the simplest methods is "completing the square."
-3x^2 +6x +6 = 0
x^2 -2x = 2 . . . . . . . . divide by -3 and add 2
x^2 -2x +1 = 2 +1 . . . . add 1 to complete the square
(x -1)^2 = 3 . . . . . . . . written as a square
x -1 = ±√3 . . . . . . . take the square root
x = 1 ±√3 . . . . . . . add 1; where the acorn hits the ground
The numerical values of these solutions are approximately ...
x ≈ {-0.732, 2.732}
The solutions to the equation say the acorn hits the ground at a distance of -0.732 behind Jacob, and at a distance of 2.732 in front of Jacob. The "behind" distance represents and extrapolation of the acorn's path backward in time before Jacob threw it. Only the positive solution is reasonable.
Britney ran 13,760 feet in total during practice.