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Evgesh-ka [11]
3 years ago
8

Please help me with both problems thank you so much!!

Mathematics
2 answers:
motikmotik3 years ago
6 0
The one on the left is -5/6
The one on the right is 1/21
ohaa [14]3 years ago
5 0
E. -5/6
F. 1/21
That’s the answer
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From the given graph, the image is a trapezoid.
Therefore,
The first option, "t<span>he polygon is a rectangle" is incorrect.
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A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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3 years ago
0.1 × 0.1 represent​
MariettaO [177]

Answer:

0.01

Step-by-step explanation:

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