Answers
9(x + y)
(7 - a)(b)
The Distributive Property is used in algebraic expressions to multiply a
single term and two or more terms which are inside a set of parentheses.
In the case of x(2y), there is only
one term inside the parenthesis
In the case of 9(x ∙ y), the distributive
property is not used because (x ∙ y) = xy which means only one term will be
multiplied by the term outside the parenthesis (9)
In the case of 9(x + y), the distributive
property is used because the two terms in the parenthesis (x and y) will be
multiplied by the term outside the parenthesis (9)
9(x + y) = 9*x + 9*y (by applying the distributive property)
In the case of (7 ∙ a)(b), the distributive
property is not used because (7 ∙ a) = 7a which means only one term will be
multiplied by the term outside the parenthesis (b)
In the case of (7 - a)(b), the distributive
property is used because the two terms in the parenthesis (7 and -a) will be
multiplied by the term outside the parenthesis (b)
(7 - a)(b) = 7*b - a*b (by applying the distributive
property)
In the case of (2 ∙ x) ∙ y, the distributive
property is not used because (2 ∙ x) = 2x which means only one term will be
multiplied by the term outside the parenthesis (y)
Answer:
A,B,D
Step-by-step explanation:
right on edge
P = 2l + 2w
P = 2(119) + 2(40.40) = 238 + 80.80 = 318.80
P = 318.80
Hey!
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10x = 10
To find the constant of proportionality just take the number and divide it by 1. 10x/1 = 10. The constant of proportionality can also be found by finding the slope of an expression or graph. In this case the slope is 10.
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Thus, 10 is the constant of proportionality!
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Hope This Helped! Good Luck!
Step-by-step explanation:
Notice that, the angle QRS is external to the triangle and adjacent to the angle PRQ. According to the theorem of a external/adjacent angle, we have: m∠QRS = m∠PQR + m∠RPQ, where PQR and RPQ are internal angles.
From the hypothesis, we have:
m∠QRS =(10x−12)∘(10x−12)
m∠PQR = (3x+20)∘(3x+20)
m∠RPQ=(3x−8)∘(3x−8)
Using the first equation and replacing the hypothesis:
m∠QRS = m∠PQR + m∠RPQ
(10x−12)∘(10x−12) = (3x+20)∘(3x+20) + (3x−8)∘(3x−8)
Multiplying and applying the remarkable identity:
Then, we use a calculator to find the roots, which are:
In this case, we will see what root is the right one.
Now, we replace it into m∠QRS =(10x−12)∘(10x−12), because we need to find m∠QRS.
m∠QRS =(10x−12)∘(10x−12) = (10(4.7) - 12) (10(4.7) - 12) = (35) (35) = 1225
