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Leto [7]

Distance = subtraction
10 - (-5) = 10 + 5 = 15

The distance is 15

4 0

2 years ago

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Find the values of P for which the quadratic equation 4x²+px+3=0?

klasskru [66]

<h3><u>Correct Questions :- </u></h3>

Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .

<h3><u>Solution</u>:- </h3>

Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

For equal roots

D = 0

$\quad\green{ \underline { \boxed{ \sf{Discriminant, D = β² - 4αc}}}}$

So,

$\sf{ β² - 4αc = 0}$

Here,

α = 4
β = p
c = 3

Now,

$\begin{gathered}\implies\quad \sf p²- 4 \times 4 \times 3 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²- 48 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²=48\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{48}\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{2 \times 2 \times 2 \times 2 \times 3} \end{gathered}$

$\begin{gathered}\implies\quad \sf p=± 2\times 2\sqrt{ 3 }\end{gathered}$

$\begin{gathered}\implies\quad \boxed{\sf{p=±4\sqrt{ 3 }}}\end{gathered}$

Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-

4√3 and -4√3.

7 0

2 years ago

Please solve these coin problems:

ratelena [41]

1)
Solving from system of equations:
x- amount of 1 cent stamps
y- amount of 33 cent stamps
$\left \{ {{1*x+33*y=18,40} \atop {x+y=80}} \right.\\x=80-y\\0,01*(80-y)+0,33y=18,40\\0,8-0,01y+0,33y=18,40\\0,32y=18,40-0,8\\0,32y=17,60 /:0,32\\y=55\\x=80-55=25$
2)
x- amount of 20 cent stamops
y-amount of 34 cent stamps
From system of equations:
$\left \{ {{0,2x+0,34y=19,90} \atop {x+y=75}} \right.\\x=75-y\\0,2(75-y)+0,34y=19,90\\ 15-0,2y+0
,34y=19,90\\-0,2y+0,34y=19,90-15\\0,14y=4,90/:0,14\\ y=35\\x=75-35=40$

6 0

3 years ago

What is the area of this figure?<br><br> A. 102<br> B. 132<br> C. 168<br> D. 340

matrenka [14]

The total area of the figure is the area of the square plus the area of the rectangle plus the area of the triangle.
area of the square: (6)*(6)=36cm^2
area of the rectangle: (7)*(6)=42cm^2
area of the triangle: (1/2)*(8)*(6)=24cm^2
total area
At=36+42+24=102cm^2

8 0

3 years ago

X² - 2ax + b = 0<br>solve using completing the square

prisoha [69]

Use the formula
(b/2)*2
in order to create a new term. Solve for
by using this term to complete the square.
Cannot solve by completing the square.

5 0

3 years ago

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20 Points!please Help Thanks!In Return brainliest and special thanks