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andrey2020 [161]
3 years ago
5

About 56% of the 2553 students are in rolled in at least one honors classes how many students are in rolled in an honors class

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

The correct answer is about 1430 students.

Step-by-step explanation:

First we must analyze the information we have.

We know that 56% of 2553 students are rolled in at least one honors classes.

What we are asked to find out is what number represents that 56%, and to find out we simply multiply that number, by the total number of students and divide it by 100.

Then: 56. 2553 = 142968: 100 = 1429.68.

As we are asked for an approximate result, and we are talking about people, the number must be integer, so we will round it up and say that the result is about 1430 students.

levacccp [35]3 years ago
5 0

Answer:

1430 students

Step-by-step explanation:

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A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Two marbles are drawn from the bag.
kherson [118]

Answer:

It is the third option: (10C1) (20C1( / 50C2.

Step-by-step explanation:

The number of ways of selecting 2 marbles = the number of combination of any 2 marbles in the 50 marbles in the bag and this is 50C2. It is combinations because the order of drawing the marbles does not matter.

The number of combinations  of one being red and the other blue =  10C1 times 20C1.

So the answer is (10C1) (20C1( / 50C2.

6 0
3 years ago
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What is the difference 1/9 - 5/6 a 13/18 b 1/18 c - 1/18 d -13/18
Murrr4er [49]
1/9 - 5/6

Convert both of them into denominators of 18.

2/18 - 15/18

Subtract the numerators and keep the denominator:

-13/18
3 0
3 years ago
The length of a rectangle is 14 inches and it’s area is (42x+56) square inches. Factor the expression for the area. Write an exp
sergey [27]

Answer:

Step-by-step explanation:

Area = 42x + 56

length * width = 14* 3x + 14*4

14 * width = 14*(3x+4)

width=\frac{14*(3x+4)}{14}\\\\width=3x+4

5 0
3 years ago
Carrie has 40 more nickels than Joan has dimes. They both have the same amount of money. How many coins does each girl have? Wha
LuckyWell [14K]

Answer:

Carrie and Joan have 80 nickels and 40 dimes, respectively, and each one has an amount of money of 4 US dollars.

Step-by-step explanation:

Let be x and y the amounts of nickels and dimes that Carrie and Joan have, as c the total amount of money that both Carrie and Joan have. A nickel is a five cent coin and a dime is a ten cent coin.

The following equations are constructed after a careful reading on statement:

Carrie's amount of money:

0.05\cdot x = c (Eq. 1)

Joan's amount of money:

0.10\cdot y = c (Eq. 2)

Relation between amounts of coins:

x = y+40 (Eq. 3)

First we eliminate c by equalizing (Eq. 1) and (Eq. 2):

0.05\cdot x = 0.10\cdot y

Then, we reduce the resulting formula by (Eq. 3):

0.05\cdot (y+40) = 0.10\cdot y

y+40 = 2\cdot y

y = 40

And rest of variable are now determined:

x = 40+40

x = 80

c = 0.05\cdot (80)

c  = 4

Carrie and Joan have 80 nickels and 40 dimes, respectively, and each one has an amount of money of 4 US dollars.

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3 years ago
Use the markings in the image to answer the following questions (drawing not to scale):
katrin [286]

First of all, we have to observe this triangles separated by the height. These small and big triangles are similar according to the Angle-Angle-Angle principle.


a. We can find all of these length using the cosine of the angle, Pythagoras theorem and the principle of the similarity of triangles.


b. According to the cosine of the angle we can write that, cosθ = 12/a = 5/13 and from here a = 31.2. After finding that using Pythagoras theorem, we can write that b=\sqrt{31.2^{2}-12^{2}} = 28.8. According to the similarity of the triangles, we can write that 31.2/d = 28.8/12 and d = 13. Applying Pythagoras theorem we find that c = 5.


c. We already gave the answer for this question in part b


8 0
3 years ago
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