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3 years ago

About 56% of the 2553 students are in rolled in at least one honors classes how many students are in rolled in an honors class

Mathematics

2 answers:

Hoochie [10]3 years ago

8 0

Answer:

The correct answer is about 1430 students.

Step-by-step explanation:

First we must analyze the information we have.

We know that 56% of 2553 students are rolled in at least one honors classes.

What we are asked to find out is what number represents that 56%, and to find out we simply multiply that number, by the total number of students and divide it by 100.

Then: 56. 2553 = 142968: 100 = 1429.68.

As we are asked for an approximate result, and we are talking about people, the number must be integer, so we will round it up and say that the result is about 1430 students.

levacccp [35]3 years ago

5 0

Answer:

1430 students

Step-by-step explanation:

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igor_vitrenko [27]

Answer:

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3 years ago

There is a competition in the cinema to win free tickets. You must guess the ages of the four employees. Here are the clues: - W

jenyasd209 [6]

Answer:

Kirk is 28 years old, Brian is 36 years old, Matt is 18 years old, and the manager is 24 years old.

Step-by-step explanation:

Let $k$ be Kirk's age.

Let $b$ be Brian's age.

Let $m$ be Matt's age.

Let $m_{1}$ be the boss/manager's age.

From the information given, we can set up 4 equations:

$k+b+m+m_{1}=106$

$k=2(m_{1}-10)$

$b=2m_{1}-12$

$m=\frac{1}{2}m_{1}+6$

Rewrite the first equation, substituting $k$ , $b$ , and $m$ in terms of $m_{1}$ to get:

$2(m_{1}-10)+(2m_{1}-12)+(\frac{1}{2}m_{1}+6)+m_{1}=106$

Open up the parentheses using the distributive property (which is $a(b-c)=ab-ac$ ) and combine like terms to get:

$5.5m_{1}-26=106$

Add 26 to both sides to reach:

$5.5m_{1}=132$

Thus, $m_{1}=24$ . Substitute $24$ for $m_{1}$ in the second, third, and fourth original equations to find that $k=28$ , $b=36$ , and $m=18$ . Therefore, Kirk is 28 years old, Brian is 36 years old, Matt is 18 years old, and the manager is 24 years old. To check, you can add up all of the ages to get 106.