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LenaWriter [7]
3 years ago
8

Helpppppppppppppppppppp me

Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

6x5=30

Step-by-step explanation:

30÷5=6

n=6

6×5=30

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In a school, the ratio of soccer players to volleyball players is 4 : 1.
VLD [36.1K]
4:1 means for every four soccer player there is 1 volleyball player

that means there are four times the number of soccer players than volleyball players
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Simplify then factor
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U.s marine core semper fi
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The marked price of a television set is #480. What is the sale price if a discount of 15% is given?
Hoochie [10]

Answer:

sale price = 408

Step-by-step explanation:

480 * 15/100 = 72

sale price = 480 -72 =408 (ans)

7 0
3 years ago
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The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0
3 years ago
Read 2 more answers
Please help me with my math question<br> Will give brainliest <br> Brainliest!!!!
DiKsa [7]

Answer:

12x - 6

Step-by-step explanation:

8x - 3 + 4x - 3

12x - 6

x = - 2

6 0
3 years ago
Read 2 more answers
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