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Neporo4naja [7]
2 years ago
13

True of false Rise is the vertical change between any two points on a line

Mathematics
1 answer:
zaharov [31]2 years ago
8 0

Answer:

True

Step-by-step explanation:

brainliest

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1/2x + 6= 3x - 4<br> Solve the system of equations
shepuryov [24]
1.Combine multiplied terms into a single fraction

2. Multiply by 1

3. Subtract 6 from both sides of the equation

4.Simplify

5.Subtract 3x from both sides of the equation

6.Simplify

7.Multiply all terms by the same value to eliminate fraction denominators

8.Simplify

9.Divide both sides of the equation by the same term

10.Simplify

Solution:x=4
5 0
3 years ago
Complete the table and graph the coordinates pls sumone just tell me what to put in the table bc i ik how to do the graph brainl
denis23 [38]

Answer:

tbh what grade is this

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. Find X<br><br> A. 16.45<br> B. 15.92<br> C. 12<br> D. 11.5
love history [14]

Answer:

A is your answer

Step-by-step explanation:

4 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
The sum of 3 consecutive odd #s is 51 what are the 3#s?
kari74 [83]

Answer: 15, 17, 19

Step-by-step explanation:

8 0
3 years ago
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