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nevsk [136]
3 years ago
12

Name three fractions between 1/2 and 1

Mathematics
2 answers:
Norma-Jean [14]3 years ago
5 0
7/10 3/4 9/10. Hopefully that’s what you are looking for
V125BC [204]3 years ago
4 0

Answer:

Three fractions between 1/2 and 1 are 3/4, 4/5, and 5/6.

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Solve for x:<br> 3^2-x=5^2x+1
Vika [28.1K]

Answer:

√ 30 /5 ,  − √ 30 /5

Step-by-step explanation:

4 0
3 years ago
Find the value of x. Leave your answer in simplest radical form. The chord measures 14, the diameter measures 18. Hint: use pyth
ehidna [41]

Answer:

x = 4√2

Step-by-step explanation:

<u><em>Find the value of x. Leave your answer in simplest radical form. The chord measures 14, the diameter measures 18. Hint: use pythagorean theorem</em></u>

To solve, we will follow the steps below:

using Pythagoras theorem

opposite² +  adjacent² = hypotenuse²

14² + y² = 18²

196 + y² = 324

subtract 196 from both-side of the equation

196 -196 + y² = 324-196

y² =128

Take the square root of both-side

√y² = √128

y =√128

y = √64×2

y =√64×√2

y = 8√2

x = half of y

x = y/2

x = 8√2  ÷  2

x = 4√2

8 0
3 years ago
Help ive been hacked!!
devlian [24]
What the heck did you try changing your password
3 0
3 years ago
Read 2 more answers
The triangles are similar.
Gemiola [76]

Answer:

x=12

Step-by-step explanation:

because they are proportional, the side should be 100 so you just solve from that equation for 100.

6 0
3 years ago
Read 2 more answers
1.
RUDIKE [14]

Answer:

Answer:

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

=3

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

m = 12/20 = 0.6

size of final image = .6 x 30 = 18 cm

3 0
4 years ago
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