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2 years ago

Name three fractions between 1/2 and 1

Mathematics

2 answers:

Norma-Jean [14]2 years ago

5 0

7/10 3/4 9/10. Hopefully that’s what you are looking for

V125BC [204]2 years ago

4 0

Answer:

Three fractions between 1/2 and 1 are 3/4, 4/5, and 5/6.

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How is the function shown below related to y=x? Graph the function by translating the parent function y=x+5

AveGali [126]

Consider x=0.

The output of the function y=x is y=0.

The output of the function y=x+5 is y=0+5, or y=5.

The value 5 is not 5 less than 0, not 1/5 of 0, and not 5 times 0. Rather, it is 5 more than 0, corresponding to selection ...

... C. Each output of y=x+5 is 5 more than the corresponding output of y=x.

7 0

3 years ago

Read 2 more answers

Find the fraction of stundents enrolled in each language

blondinia [14]

Fraction of students enrolled in Chinese = $\frac{51}{126}$

Fraction of students enrolled in French = $\frac{33}{126}$

Fraction of students enrolled in Spanish = $\frac{42}{126}$

Solution:

Total number of students = 51 + 33 + 42

= 126

Number of students enrolled in Chinese = 51

Fraction of students enrolled in Chinese

$$=\frac{\text{Number of students enrolled in Chinese}}{\text{Total number of students}}$

$$=\frac{51}{126}$

Fraction of students enrolled in Chinese = $\frac{51}{126}$

Number of students enrolled in French = 33

Fraction of students enrolled in French

$$=\frac{\text{Number of students enrolled in French}}{\text{Total number of students}}$

$$=\frac{33}{126}$

Fraction of students enrolled in French = $\frac{33}{126}$

Number of students enrolled in Spanish = 42

Fraction of students enrolled in Spanish

$$=\frac{\text{Number of students enrolled in Spanish}}{\text{Total number of students}}$

$$=\frac{42}{126}$

Fraction of students enrolled in Spanish = $\frac{42}{126}$

7 0

3 years ago

Which equation is represented by the table

lyudmila [28]

Answer:

B. b = 3a + 2

Step-by-step explanation:

We can write the equation in slope-intercept form as b = ma + c, where,

m = slope/rate of change

c = y-intercept/initial value

✔️Find m using any two given pair of values, say (2, 8) and (4, 14):

Rate of change (m) = change in b/change in a

m = (14 - 8)/(4 - 2)

m = 6/2

m = 3

✔️Find c by substituting (a, b) = (2, 8) and m = 3 into b = ma + c. Thus:

8 = 3(2) + c

8 = 6 + c

8 - 6 = c

2 = c

c = 2

✔️Write the equation by substituting m = 3 and c = 2 into b = ma + c. Thus:

b = 3a + 2

4 0

3 years ago

Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17

Luden [163]

The larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

$ax^2 + bx + c = 0$

Then its roots are given as:

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

The given quadratic equation is

$y = -2.2x^2 + 63.5x - 17$

now, the roots of the equation are

$x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}$

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

#SPJ1

7 0

2 years ago

I really need help with this Triangle problem.

julia-pushkina [17]

Answer:

x = 10

y = 20

Step-by-step explanation:

$\tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20$

4 0

3 years ago