You can use this to help you. label the triangle like the picture and use the equations. I hope this helps.
Answer:
The owner should gather more.
Step-by-step explanation:
He should gather more so he can make sure he is correct.
Answer:
![\theta_1 \ n\ \theta_2 = 120, 240](https://tex.z-dn.net/?f=%5Ctheta_1%20%5C%20n%5C%20%5Ctheta_2%20%3D%20120%2C%20240)
Step-by-step explanation:
The question is incomplete, as the angles of rotation are not stated.
However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself
We have:
![Nonagon = 9\ sides](https://tex.z-dn.net/?f=Nonagon%20%3D%209%5C%20sides)
![Hexagon = 6\ sides](https://tex.z-dn.net/?f=Hexagon%20%3D%206%5C%20sides)
Divide 360 degrees by the number of sides in each angle, then find the multiples.
<u>Nonagon</u>
![\theta = \frac{360}{9} =40](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B360%7D%7B9%7D%20%3D40)
List the multiples of 40
![\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%2040%2C%2080%2C%20120%2C%20160%2C%20200%2C%20240%2C%20280%2C%20320)
<u>Hexagon</u>
![\theta = \frac{360}{6} =60](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B360%7D%7B6%7D%20%3D60)
List the multiples of 60
![\theta_2 = 60, 120, 180, 240, 300](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%2060%2C%20120%2C%20180%2C%20240%2C%20300)
List out the common angles
![\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%2040%2C%2080%2C%20120%2C%20160%2C%20200%2C%20240%2C%20280%2C%20320)
![\theta_2 = 60, 120, 180, 240, 300](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%2060%2C%20120%2C%20180%2C%20240%2C%20300)
![\theta_1 \ n\ \theta_2 = 120, 240](https://tex.z-dn.net/?f=%5Ctheta_1%20%5C%20n%5C%20%5Ctheta_2%20%3D%20120%2C%20240)
This means that, only a rotation of
will lift both shapes onto themselves, when applied to both shapes.
The other angles will only work on one of the shapes, but not both at the same time.
Answer:
PART A: Inequality (a)
Solve for y
The graph of y ≥ ⅓(8-x) is represented by the upper red line and all points in the shaded area below it. The line is solid because points on the line satisfy the conditions.
Inequality (b)
Solve for y
The graph of y ≥ 2 - x is represented by the lower blue line and all points in the shaded area above it. The line is solid because points on the line satisfy the conditions. The solution lies in the purple area. It consists of all combinations of x and y that make y ≥ ⅓(8 - x) and y ≥ 2 - x. A practical but not a mathematical condition is that all values of x and y must be zero or positive numbers (for example, you can't have -2 servings of food), so I have plotted only the numbers in the first quadrant.
PART B: If a point is a solution of the system, then the point must satisfy both inequalities of the system.
For x=8, y=2. Verify inequality A is not true. So the point does not satisfy inequality A. Therefore, the point is not included in the solution area for the system.
PART C: I choose the point (3,1) which is included in the solution area for the system.
That means Michelle buys 3 serves of dry food and 1 serving of wet food.
Step-by-step explanation:
Plz mark Brainliest?
Answer:
below :)
Step-by-step explanation:
1) 12
2}3/2
3)224.64
4)2 quarters
5)w=50
6)m=6y+7
7)42/6=7 x=6