In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
The sides of the box are 12in by 12in by 30in.
The interior diagonal =[12^2+12^2+30^2]0.5
=[144+144+900]^0.5
=1188^0.5
The final answer is 34.47in.
My deepest apology if this is not what you meant.
= 34.47in.
Can you put this in English so I can help you please
Answer:
1 hour and 20 minutes
Step-by-step explanation:
45+25+10=80 minutes which equal 1 hour and 20 minutes
Answer:
2.8
Step-by-step explanation:
ur welcome i hope this helps
