R(t) = 4t
A(r) = π(r^2)
a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)
b) t = 4,
A(4) = 16*3.14*(16)^2 = 12,861.44
Answer:
The journal entries as well as the T-accounts for August transactions are found in the attached spreadsheet.
Step-by-step explanation:
Initially, the transactions were posted individually in the journal and ultimately the related ones were combined together in the T-accounts.
For instance, cash related transactions are posted in the cash T-account to ascertain the true cash position as at the end of the quarter.
Answer:
Step by step explanation:
Answer:
2.56
Step-by-step explanation:
The equation they dive u: d = 16t^2, so in the question they said what's the distance, d, if t = 0.4
So you just have to replace t with 0.4:
d = 16t^2
d = 16(0.4)^2
d = 16(0.16)
d = 2.56
Answer:
The true statement about Kendra's sample is:
b) Kendra's samples are precise but not accurate.
Step-by-step explanation:
a) Data and Calculations:
Average age of dogs currently alive = 4.8 years
Average ages of dogs in Kendra's sample
Week Average Age (in years)
1 3.7
2 3.8
3 4.2
4 4.1
5 3.9
6 3.9
7 4.0
Total 27.6
Mean = 3.9 (27.6/7)
b) Accuracy refers to how close Kendra's sample mean age of dogs is to the average age value as stated in the Modern Dog Magazine. While the Magazine stated an average age of 4.8 years, Kendra's sample produced a mean of 3.9 years. On the other hand, precision refers to how close Kendra's sample measurements are to each other. With a mean of 3.9 years, the sample measurements are very close to each other. Therefore, we can conclude that "Kendra's samples are precise but not accurate."
