HELP CONGRUENCE BY SAS AND SSS WILL GIVE BRAINLIEST IF CORRECT

Mathematics

1 answer:

balu736 [363]3 years ago

5 0

Answer:

1. Cong SSS 2.Cong SSS 3.Not Cong 4.Not Cong 5.Cong SAS 6.Cong SSS 7.Cong SAS 8.Cong SSS 9.Cong SSS 10.Cong SAS 11.d 12.a 13.a 14.b 15.a

Step-by-step explanation:

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Suppose that the function f ( x ) = 2x + 12 represents the cost to rent x movies amonth from an internet movie club. Makayla now

Dafna11 [192]

$x=7\ \ \ \ \Rightarrow\ \ \ f(x)=2\cdot7+12=14+12=26\ [\$]\\\\\$26-\$10= \$16\\\\Ans.\ Makayla\ need\ \ \ \$16.$

3 0

3 years ago

Read 2 more answers

The depth of a lake, d, varies directly with r, the amount of rainfall last month. if k is the constant of variation, write an e

irina1246 [14]

Answer:
d = kr

Explanation:
We know that the depth (d) varies directly with the amount of rain (r).
This means that as the amount of rain increases, the depth increases and vice-versa.
The depth would depend on r multiplied by a constant of variation (k)

Translating this into equation, we would get the following:
d = kr

Hope this helps :)

4 0

3 years ago

The manager of a pizza chain in Albuquerque, New Mexico, wants to determine the average size of their advertised 16-inch pizzas.

erastova [34]

Answer:

n=50

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=16.10$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=1.8 represent the sample standard deviation

n=25 represent the sample size

2) Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=\pm 1.96$

Since we assume that we are taking a bigger sample then we can replace the t distribution with the normal standard distribution, and we can assume that th population deviation is 1.8. The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)