It is given that the sample size is 17.
So degrees of freedom is 16.
The confidence level is 80%.
Use the t table or a tool to find the critical t value as below:
The one tail t value for 80 percent confidence is 0.865 using t table.
So the critical value is 0.865.
The area under a graph is given by the integral of that function, evaluated in the interval of interest:
![\displaystyle \int_{-3}^2 x^2+4\;dx = \left[\dfrac{x^3}{3}+4x\right]_{-3}^2 = \left[\dfrac{2^3}{3}+4\cdot 2\right]-\left[\dfrac{(-3)^3}{3}+4\cdot(-3)\right] = \left[\dfrac{8}{3}+8\right]-\left[-9-12\right] = \dfrac{32}{3}+21 = \dfrac{95}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_%7B-3%7D%5E2%20x%5E2%2B4%5C%3Bdx%20%3D%20%5Cleft%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%2B4x%5Cright%5D_%7B-3%7D%5E2%20%3D%20%5Cleft%5B%5Cdfrac%7B2%5E3%7D%7B3%7D%2B4%5Ccdot%202%5Cright%5D-%5Cleft%5B%5Cdfrac%7B%28-3%29%5E3%7D%7B3%7D%2B4%5Ccdot%28-3%29%5Cright%5D%20%3D%20%5Cleft%5B%5Cdfrac%7B8%7D%7B3%7D%2B8%5Cright%5D-%5Cleft%5B-9-12%5Cright%5D%20%3D%20%5Cdfrac%7B32%7D%7B3%7D%2B21%20%3D%20%5Cdfrac%7B95%7D%7B3%7D)
Formula is Area/ Pie
78.5/3.14 = 25
Answer:
I think its 14 students
Step-by-step explanation:
40%x35=14
Answer:
Yes, Amanda has enough materials to make the concrete mix.
Step-by-step explanation:
Total units = 1+3+5
= 9
9 units = 630kg
1 unit = 630kg ÷ 9
= 70kg (Less than 80kg of cement, more than enough)
3 units = 3 × 70kg
= 210kg (Less than 215kg of sand, more than enough sand)
5 units = 5 × 70kg
= 350kg (Less than 370kg of gravel, more than enough gravel)
