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Alex73 [517]
3 years ago
11

How to get fast frontend development online job as a beginner?​

Computers and Technology
1 answer:
mezya [45]3 years ago
3 0

Answer:

hmmm well what is your magager?? every job will ask you what you can do.

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Answer:

It is address to send electronic mails

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The library Wi-Fi kiosk requires a symmetric connection to the Internet. Which WAN technology would probably be the least expens
kenny6666 [7]

Answer:

The answer is IP-sec.

Explanation:

0.75 miles of range is a low distance for a WAN (Wide Area Network) so a point-to-point WAN tehcnology such as IP-sec or SD-WAN can be preferred. But the least expensive option would be choosing IP-sec as specified in the question.

I hope this answer helps.

6 0
3 years ago
Compared to a virtual image, a real image
Musya8 [376]
D.  can be viewed on a screen

100% sure

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4 years ago
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When initiating a connection how does tcp establish a connection?
Pani-rosa [81]
It uses a 3-way handshake

1. SYN from client to server.
2. SYN-ACK from server to client.
3. ACK from client to the server.

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4 0
3 years ago
Before making a dish, we want to check whether we already have the necessary ingredients in our pantry or whether we need to go
Leona [35]

Answer:

class Pantry(AD):

              def __init__(self, ingredients):

""" We initialize the Pantry class by passing the ingredients that were passed in to the initializer for the superclass AD"""

              super().__init__(ingredients)

              def needed_ingredients(self, recipes):

""" Given a list of recipes, computes which ingredients to buy, and in which quantity to be able to make all recipes. Can be implemented in 10 lines of code."""

              # define the object new_pantry to contain the ingredients needed

               new_pantry = Pantry({})

                ingredients_present = self

                # loop over the recipes in the list

                for recipe in recipes:

                        # convert ingredients of recipe from AD to Pantry

                        ingredients = Pantry(recipe.ingredients)

                        # subtract the recipe's ingredients from ingredients_present

                          ingredients_present = ingredients_present - ingredients

                        # loop over the ingredients_present for key in ingredients_present:

                       # if any ingredients's quantity < 0, add it to new_pantry

                                                           if ingredients_present[key] < 0:

# check if ingredient is present in new_pantry, add the quantity to existing quantity

                                                               if key in new_pantry:

                                            new_pantry[key] += -1*(ingredients_present[key])

else: # if ingredient is not present in new_pantry, make a new entry for the ingredient

                                               new_pantry[key] = -1*(ingredients_present[key])

ingredients_present[key] = 0      # set the quantity of the ingredient in ingredients_present to 0

Explanation:

I believe everything else is provided in the question.

Copy all the details you were provided in the question as it is and add the needed_ingredients in the Pantry class.

If you are getting any assertion error, Update the code to set the negative quantities in ingredients_present to 0

6 0
3 years ago
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