Question

Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following strings:
madam, abba, 22, 67876, 444244, trymeuemyrt

Modify the function isPalindrome of Example 6-6 so that when determining whether a string is a palindrome, cases are ignored, that is, uppercase and lowercase letters are considered the same.

The isPalindrome function from Example 6-6 has been included below for your convenience.

bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++) {
if (str[i] != str[length – 1 – i]) {
return false;
} // if
} // for loop
return true;
}// isPalindrome

Your program should print a message indicating if a string is a palindrome:

madam is a palindrome

Answer 1

Answer:

Explanation:

bool isPalindrome(string str)

{

   int length = str.length();

   for (int i = 0; i < length / 2; i++) {

      if (str [i] != str [length – 1 – i]) {

         return false;

         }

    }

cout << str << "is a palindrome";

return true;

}