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maw [93]
3 years ago
13

Charlie's puppy max weighs 10 pounds. How many ounces does Max weigh?

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

160 ounces

Step-by-step explanation:

16 ounces=1 pound

10x16=160

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Elijah put 2x+3 dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount i
ella [17]

I believe the answer would be $79.50.

7 0
2 years ago
Simplify this answer pls
ipn [44]

Answer:

D

Step-by-step explanation:

when it's a power of the power we multiply the powers to get a single value for the power.

(6^(1/4))^4=6^(4*(1/4)) (4*(1/4)=1)

=6^1=6

so the answer is D

7 0
3 years ago
Helppppppppppppppppppppppppppp
NISA [10]
Area of cylinder = 2 pi r h + 2 pi r^2
= 2 * 3.14 * 4 * 12 + 2 * 3.14 * 4^2
= 301.44 + 100.48
Area of cylinder = 401.92 cm^2
4 0
2 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
Solve the following system of equations by substitution
den301095 [7]

Answer:

c.  (2, -18)

Step-by-step explanation:

y = -5x - 8

y = 3x - 24

3x - 24 = -5x - 8

8x = 16

x = 2

y = 3x - 24

y = 3(2) - 24

y = 6 - 24

y = -18

Answer: c.  (2, -18)

5 0
2 years ago
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