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RoseWind [281]
2 years ago
11

Suppose f(x) = x² and g(x)= (1/5x)^2

Mathematics
1 answer:
Alisiya [41]2 years ago
4 0

Answer:

B. The graph of g(x) is the graph of f(x) vertically stretched by a factor of 5.

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My estimate was 2,808 is that a reasonable estimate and why
vova2212 [387]
<span>My estimate was 2,808 is that a reasonable estimate and why

312*9

9*2=18>>9*10=90>>9*300=2700

2700+18+90=>>2,808</span>
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3 years ago
(5⅐)⁴=( ) OPTIONS : A.) (5⁴)⅐ B.)5²⁸ C.)(5)¹/²⁸ D.)(5)⁷/⁴​
NemiM [27]

Answer:

a

Step-by-step explanation:

4*1/7

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3 years ago
After 4 new students joined a class, the class had 32 students.
AleksandrR [38]

Answer:

32-4=n or 4+n=32

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3 years ago
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Answer:

5\sqrt{3} - 4

Step-by-step explanation:

\sqrt{(4-5\sqrt{3}  )^{2} }

5\sqrt{3}  - 4

3 0
3 years ago
A California licence plate consists of a sequence of seven symbols: number, letter, letter, letter, number, number, number, wher
tino4ka555 [31]

Answer:

There is a 44.73% probability that all symbols are different.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

There are 26 total letters and 10 total digits.

The plate has the following format:

number, letter, letter, letter, number, number, number

Total outcomes

Each number can have 10 values.

Each letter can have 26 values.

There are four numbers and 3 letters.

So there are

10^{4}*26^{3} = 175760000 possible plates

Desired outcomes

We cannot have repeated values.

So, for example, the first number can be any of the 10 digits. The second can be any of them, bar the first one. So 9 possible digits

The same logic for the letters, 26, then 25, then 24.

So there are

10*26*25*24*9*8*7 = 78624000 plates in which all symbols are different.

(a) What is the probability that all symbols are different

P = \frac{78624000}{175760000} = 0.4473

There is a 44.73% probability that all symbols are different.

7 0
3 years ago
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