All categories

2 years ago

How many 2/5 teaspoon doses of medicine are in a container that holds 18/10 teaspoon of medicine?

Mathematics

1 answer:

Volgvan2 years ago

3 0

Answer: 4.5

Step-by-step explanation:

You might be interested in

Guys can u help me asap ?? i need explaination aloong the answer

Alisiya [41]

Answer:

5225 x 5/100 = 261.25

5225 - 261.25 = 4963.75

Step-by-step explanation:

We know that % means a 100 so if they say they allowed a 5% discount then that would be 5/100.

You will take the fraction and multiple it with the original price. It will then give you the discount price, you will then need to subtract the discounted amount from the original sale price which is 5225. Then you will get your final answer.

;-)

5 0

2 years ago

Please help me with this it might look easy to you but not to me :

Rasek [7]

Answer:

Step-by-step explanation:

5/6 =0.8333

12x0.8333 = 10

7 0

2 years ago

Sam wants to know how long it will take to fill his baby pool that holds 24 gallons. after 1 minute, there are 2 gallons of wate

saul85 [17]

B 12 because you divide 24/2=12

3 0

2 years ago

Read 2 more answers

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

Tony is a medical sales representative. His company has set a goal for him to sell 4,200 bottles of a new medicine in 3 months i

BlackZzzverrR [31]

That answer would be 4,200/3=1,400

5 0

2 years ago