4x = (130 - 2x) so x = 65/3
(3y + 40) + (130 -2x) = 180 because the angles are supplementary
plug in x
3y + 40 + 130 - 2(65/3) = 180
so 3y = 95/3
therefore y = 95/6
Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
The answer is variant A.
Because:
if the two angles of a triangle are congruent to two angles of the other triangle , this triangles are similar
F(x)=2x
G(x)=x+5
Now
F(g(x))=2(x+5)
=2x+10
G(f(x))=2x+5
To solve this problem you must apply the proccedure shown below:
1. You have that the time, given in the problem above, is written in decimal form.
2. To express this time in words, you must begin from left to right. First, write the digits before the point (58) and after the points (329) as whole numbers. Then, finish it writting the place name of the last digit, as following:
(Note: The point is expressed as "and").
58.329: Fifty eigth and three hundred twenty nine thousandths.
Therefore, the answer is: Fifty eigth and three hundred twenty nine thousandths.
