Question

Point J (−4, −6) and point K (4, 4) are located on a coordinate grid. A blank one is shown above.

Answer 1

Square root. (-4-4)^2 +(-6-4)^2
Square root 64+100
Square root 164
C.

Answer 2

Answer:

$c)13\: units$

Step-by-step explanation:

If we consider the JK as the hypotenuse of a triangle, and  L as another point (perpendicular to K) then we'd have a triangle. Therefore, the Distance formula is given by deriving it from Pythagorean Theorem, as it follows:

$\overline{JK}=hypotenuse\:\overline{JL}=leg,\overline{KL}=leg\\a^{2}=b^{2}+c^{2}\\a^{2}=(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}\\D_{JK}=\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}\Rightarrow D_{JK}=\sqrt{(-4-4)^{2}+(-6-4)^{2}}\\D_{JK}=\sqrt{(-8)^{2}+(-10)^{2}}\Rightarrow D_{JK}=\sqrt{164}\Rightarrow D_{JK}\approx 13$