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3 years ago

Please help i suck at math

Mathematics

1 answer:

Andrews [41]3 years ago

6 0

Slope is rise/run
so, you go up 4 times and run across 3 times, this is a positive slope, so the slope is
slope: 4/3
the y-intercept is the line that passes the y-axis, (0, -5),
y-intercept: -5

put it together
4/3x-5

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Can someone explain to me how to do this and give me the answer please?

pantera1 [17]

Answer:

To find x, y, z, p and q, you need to know about the property of Rhombus.

13y + 10 = 7y + 16 (pair of equal opposite sides)

=> 6y = 6

=> y = 1

x = 7x + 16 (2 equal adjacent sides)

= 7*1 + 16

=23

z = 90 deg (angle between 2 diagonals)

q = 22 deg (isosceles triangle)

p = 90 - 22 = 68 deg (right triangle)

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3 years ago

leos total bill at the blue lobster ame to $45.90. He wanted to leave a 20% tip what would the total cost with the be?

elena-s [515]

To find the total amount Leo should give, simply find the 20% of his bill then add it.

Total cost = $45.90 + ($45.90 × 0.20)
Total cost = $45.90 + $9.18
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Therefore, Leo should give $55.08 in total to leave a 20% tip.

7 0

3 years ago

Read 2 more answers

If UW =9x-9, what is UW in units

mash [69]

Answer:

if UW = 9x-9 then UW is 5 in units

8 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by: