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Angelina_Jolie [31]

4 years ago

12

There are 10 to the 6th power millimeters in one kilometer. The distance from Dana’s house to her uncles house is 4 to the 4th p

ower kilometers. What is this distance in millimeters

1 answer:

Alex4 years ago

8 0

The answer is essentially 4^4 * 10^6

4^4 is 256, and 10^6 = 1,000,000

Knowing this, the answer should be 256,000,000

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Find the area pls- i need help

Tresset [83]

Answer:

1. 36 sq un

2. 40 sq un

3. 20 sq un

Step-by-step explanation:

The answer for number one is 36 square units because the rectangular area is 24 sq un and the triangular area is 12 sq un so I added them to get 36 sq un. The second answer is 40 sq un because if you cut the shape into 2 shapes you get 2 equal trapezoids. Each trapezoid is 20 sq un so I multiplied it by two to get 40 sq un. The third answer is 20 because the side triangles are 2 sq un each and the square on the bottom is 16 sq un. By the way, sq un means square units lol.

3 0

3 years ago

Read 2 more answers

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

Find the point at which the line f(x)=2x+10 intersects the line g(x)=−3x−5 .

k0ka [10]

9514 1404 393

Answer:

(x, y) = (-3, 4)

Step-by-step explanation:

A graphing calculator answers this question quickly. The point of intersection is (-3, 4).

__

The lines intersect where f(x) = g(x).

2x +10 = -3x -5

5x = -15 . . . . . . . . add 3x-10

x = -3 . . . . . . divide by 5

f(-3) = 2(-3) +10 = 4 . . . . . find the y-coordinate

The point is (-3, 4).

8 0

3 years ago

What is 3/7 × 5/6 thanks

aleksley [76]

3/7*5/6

cross out 3 and 6

divide by 3

3/3= 1

6/3= 2

1/7*5/2

mutiply the denominators together

7*2= 14

mutiply the numerators together

1*5= 5

Answer:

5/14

3 0

3 years ago

Read 2 more answers

Use the points A(4, 4) and B(4, −5). Complete the description of segment AB and find its length.

Svet_ta [14]

Use the points A(4, 4) and B(4, −5)

(1) (a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same

Here in A(4, 4) and B(4, −5) , the x values are same so the segment AB is a Vertical . The length is the difference between y values ( 4 -(-5)) = 9

Segment AB is a Vertical segment that is 9 units long.

(2) Describe the image of segment AB under the transformation

(x, y) ----> (x, 2y)

A(4, 4) -----> (4, 8)

and B(4, −5) ---> (4, -10)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 8 -(-10)) = 18

The image of segment AB is a Vertical segment that is 18 units long.

(3) Describe the image of segment AB under the transformation

(x, y) ----> (x + 2, y)

A(4, 4) -----> (6, 4)

and B(4, −5) ---> (6, -5)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 4 -(-5)) = 9

The image of AB is a Vertical segment 2 units to the right of the original segment that is 9 units long.

8 0

3 years ago