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Angelina_Jolie [31]
3 years ago
12

There are 10 to the 6th power millimeters in one kilometer. The distance from Dana’s house to her uncles house is 4 to the 4th p

ower kilometers. What is this distance in millimeters

Mathematics
1 answer:
Alex3 years ago
8 0

The answer is essentially 4^4 * 10^6

4^4 is 256, and 10^6 = 1,000,000

Knowing this, the answer should be 256,000,000

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sleet_krkn [62]

Answer:

15x*45 i think

Step-by-step explanation:

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3 years ago
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A dog is given a dosage of 100 mg of antibiotics. The amount of antibiotics in the dog's bloodstream will decrease by 40% each h
jek_recluse [69]

After each hour 60% ( or 0.60) of the drug will be present.

The equation is A = 100(0.6)^t where t = time in hours. (answer)

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3 years ago
Which type of transformation is described by (x, y)<br> -&gt;<br> + (x + 3, y — 2)?
creativ13 [48]

Answer:

(x, y) → (x+3, y-2) means Translation 3 units left and 2 units down.

Step-by-step explanation:

Given the rule of transformation:

(x, y) → (x+3, y-2)

If we move horizontally 3 units to the right, 3 is added to the x-coordinate of any given point, and then 2 units down.

In other words,

(x, y) → (x+3, y-2) means Translation 3 units left and 2 units down.

For example,

Let say if we have the point A(4, 5)

Using the translation rule:

(x, y) → (x+3, y-2)

A(4, 5) → A'(4 + 3, 5 - 2) → A'(7, 3)

Therefore, the new position of A(4, 5) after translating 3 units left and 2 units down would be: A'(7, 3)

4 0
3 years ago
A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo
katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the boxV=x^2z

Volume of the box=12 ft^3\\

Therefore, x^2z=12\\z=\frac{12}{x^2}

The material for the base costs \$0.17/ft^2, the material for the sides costs \$0.10/ft^2, and the material for the top costs \$0.13/ft^2.

Area of the base =x^2

Cost of the Base =\$0.17x^2

Area of the sides =4xz

Cost of the sides==\$0.10(4xz)

Area of the Top =x^2

Cost of the Base =\$0.13x^2

Total Cost, C(x,z) =0.17x^2+0.13x^2+0.10(4xz)

Substituting z=\frac{12}{x^2}

C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}

To minimize C(x), we solve for the derivative and obtain its critical point

C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2

Recall: z=\frac{12}{x^2}=\frac{12}{2^2}=3\\

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0
3 years ago
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professor190 [17]

Answer:

The answer is 33.2*F (72.3*F - 39.1*F because the temp. is *dropping* 39.1*F)

Step-by-step explanation:

If there is a negative change in temp. then that is just like subtracting the change from the base degree (F)

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