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Otrada [13]
3 years ago
15

Find the area of the shaded region. Round to the nearest tenth

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0

Answer: 817.9

Step-by-step explanation:

area of sector : 150/360 x 3.14 (pi) x (27.8)^2 = 1011.1323

area of circle: 1/2 x 27.8^2 x sin150 = 193.21

subtract area of sector from area of circle to get area of shaded region :)

Sophie [7]3 years ago
4 0
Answer :

57770

Solution :

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Step-by-step explanation:

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8 0
3 years ago
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The coordinate plane below represents a community. Points A through F are houses in the community.
murzikaleks [220]
A1) One possible set of inequalities is
  x +y > 2
  y -x < 4

A2) The lines are graphed as though the inequality were an equal sign. Since the inequality does not include the "or equal to" case, the lines are drawn dashed. In each case, the area to the right of the line is shaded.

B) Points A and B are solutions to the system if they are in the doubly-shaded region (which they are). In the graph here, that region is darker orange. (For this purpose, you need to ignore the green region, which overlaps part of the solution space.

C) The houses Billy is interested in are found by graphing the inequality and identifying the houses in its solution space. (Those houses are B and C.) Alternatively, you can evaluate the inequality for each of the house coordinates and see which ones give "true."

7 0
3 years ago
Multiply 6/13 and 7/22 in simplest form​
vesna_86 [32]

Answer:

21/143

Step-by-step explanation:

If it was simplified into a decimal it would be .146853

8 0
4 years ago
Is the graph increasing decreasing or constant?
Sloan [31]

The answer in constant because there is no change in the graphing.

8 0
3 years ago
Simplify : 9 Sin A +3 cosec A + 10sin A- 13 CosecA<br>​
Shtirlitz [24]

Answer:

19Sin A - (10/sin A)

Step-by-step explanation:

We want to simplify;

9Sin A + 3cosec A + 10sin A - 13Cosec A

Let's rearrange it for ease of addition;

(9Sin A + 10sin A) + (3cosec A - 13Cosec A)

>> 19Sin A - 10cosec A

Now, from trigonometric ratios, we know that; Cosec A = 1/Sin A

Thus; 10cosec A = 10/sin A

Thus, we now have;

19Sin A - (10/sin A)

6 0
3 years ago
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