I need help on this can someone please help me ?

0 A maker of a certain brand of low-fat cereal bars claims that the average saturated fat content is 0.5 gram. In a random sampl

balandron [24]

Answer:

The first step is to determine the average

$x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475$

The exercise says it’s a normal distribution: (n=8)

$s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183$

According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained

$t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\ t= -0,3860$

The variable t has 7 grade to liberty, we calculate the p-value as:

$2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108$

This value is very high, therefore the hypothesis is not rejected

7 0

3 years ago

4/16 Being Reduced Is ?

mamaluj [8]

The answer is 1/4 because all you have to really do is simplify

4 0

3 years ago

Line A: y=-1/2x+3

sashaice [31]

A) For the equation $y=- \frac{1}{2}x+3$ , the slope is $- \frac{1}{2}$ .
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if $m=- \frac{1}{2}$ , the slope is $- \frac{1}{2}$ .

B) Since this equation is in the same form, you just find what m is equal to.
Since $m=2$ , that's the slope.

For the solution, set $y=- \frac{1}{2}x+3$ equal to $y=2x-4$ , so it would be put together like this:
$y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667$
So your answer is -4.667.

8 0

3 years ago

Consider the following functions.G(x) = 4x2; f(x) = 8x(a)

noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form $4x^2+C$ is an antiderivative of 8x

Step-by-step explanation:

A function F is an antiderivative of the function f if

$F'(x)=f(x)$

for all x in the domain of f.

(a) If $f(x) = 8x$ , then $G(x)=4x^2$ is an antiderivative of f because

$G'(x)=8x=f(x)$

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of f.

(b) Because

$\frac{d}{dx}(4x^2)=8x$

then $G(x)=4x^2$ is an antiderivative of $f(x) = 8x$ . Therefore, every antiderivative of 8x is of the form $4x^2+C$ for some constant C, and every function of the form $4x^2+C$ is an antiderivative of 8x.

8 0

3 years ago

Find the values of x and y

ale4655 [162]

Answer:

idek

Step-by-step explanation:

5 0

2 years ago

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