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Nitella [24]
3 years ago
5

I need help on this can someone please help me ?

Mathematics
1 answer:
leonid [27]3 years ago
5 0
Slope is 1!!!!!!!!!!!!
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0 A maker of a certain brand of low-fat cereal bars claims that the average saturated fat content is 0.5 gram. In a random sampl
balandron [24]

Answer:

<em>The first step is to determine the average </em>

x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475

<em>The exercise says it’s a normal distribution: (n=8)</em>

s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183

<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained </em>

<em />

t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\  t= -0,3860

<em>The variable t has 7 grade to liberty, we calculate the p-value as: </em>

2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108

This value is very high, therefore the hypothesis is not rejected

7 0
3 years ago
4/16 Being Reduced Is ?
mamaluj [8]
The answer is 1/4 because all you have to really do is simplify
4 0
3 years ago
Line A: y=-1/2x+3
sashaice [31]
A) For the equation y=- \frac{1}{2}x+3, the slope is - \frac{1}{2}.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if m=- \frac{1}{2}, the slope is  - \frac{1}{2}.

B) Since this equation is in the same form, you just find what m is equal to.
Since m=2, that's the slope.

For the solution, set y=- \frac{1}{2}x+3 equal to y=2x-4, so it would be put together like this:
y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667
So your answer is -4.667.
8 0
3 years ago
Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

8 0
3 years ago
Find the values of x and y
ale4655 [162]

Answer:

idek

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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