Question

(1-x)²-(-x-2)×(2x+3) can someone explain how to solve this step by step please

Answer 1

Remember pemdas when possible
((1-x)^2)-(-x-2)*(2x+3)
Expand the exponent
(1-x)(1-x)-(-x-2)(2x+3)
Foil the first half
(1-x-x+(x^2))-(-x-2)(2x+3)
Combine like terms in first half
((X^2)-2x+1)-(-x-2)(2x+3)
Foil second half
((X^2)-2x+1)-((-2(x^2))-4x-3x-6)
Combine like terms in second half
((X^2)-2x+1)-((-2(x^2))-7x-6)
Multiply in the negative for the second half
((X^2)-2x+1)+((2(x^2))+7x+6)
Remove unnecessary parentheses
(X^2)-2x+1+2(x^2)+7x+6
Reorganize
2(x^2)+(x^2)+7x-2x+6+1
Combine like terms and you’re done
3(x^2)+5x+7