7 multiplied by 11 is 77. And to get 462, (and based on the given information), we can conclude that it is 3*2*7*11.
What type of teacher would give a frustrating problem like this?!?
Answer:
tan a + cot b
Step-by-step explanation:
It's already simplified.
There are alternate forms like
![sec(a)csc(b)cos(a-b)\\\\sec(a)csc(b)[sin(a)sin(b)+cos(a)cos(b)]\\\\\frac{sin (a)}{cos (a)} +\frac{cos(b)}{sin(b)}](https://tex.z-dn.net/?f=sec%28a%29csc%28b%29cos%28a-b%29%5C%5C%5C%5Csec%28a%29csc%28b%29%5Bsin%28a%29sin%28b%29%2Bcos%28a%29cos%28b%29%5D%5C%5C%5C%5C%5Cfrac%7Bsin%20%28a%29%7D%7Bcos%20%28a%29%7D%20%2B%5Cfrac%7Bcos%28b%29%7D%7Bsin%28b%29%7D)
Answer:

Step-by-step explanation:
We are given that:

Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:

So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:

Answer:
1. keep counting
2. He can do 5 times 3 to get to the 15th shape and then say 2 more to get the 17th shape.
(The 17th shape would be triangle)