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3 years ago

1 divided by 2/6 please help

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Answer:

Step-by-step explanation:

$1 \div \frac{2}{6} \\ \\ = 1 \times \frac{6}{2} \\ \\ = 1 \times 3 \\ \\ = 3$

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The volume of a cylinder varies jointly as the square of the radius and the height. If the volume is 28pi cubic inches when the

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Answer:

1584 cu in.

Step-by-step explanation:

Since the volume varies jointly with the radius and height we have an equation V = kr^2h where k is the constant of variation

28 = 2^2(7)k = 28k

k = 1

Now V = r^2h

V = (12)^2(11) = 144(11) = 1584 cu in.

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3 years ago

How many 3 number combinations are possible if you can't repeat the numbers? The numbers range from 0-39

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Answer: 49600

Step-by-step explanation: There are 40 ways to choose the first number

and there are 40 ways to choose the second number.

Now we take some examples to determine how many choices there are for

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If the second number is 23, then the 3rd number cannot be any of these

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numbers away from 23. Same for all other 40 second numbers.

Let's look at a second example which includes some on both sides of 0.

If second number is 2, we couldn't choose any of the 9 numbers 38,39,0,1,2,3,4,5,6.

So thats 40-9 or 31 choices for the 3rd number.

Answer 40*40*31 = 49600 ways.

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Read 2 more answers

Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0

Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: $x^4+9x^2-4x^2-36$

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: $x^2(x^2+9)-4(x^2+9)$

Now you can rewrite this as $(x^2-4)(x^2+9)$ , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is $a^2-b^2=(a+b)(a-b)$ . Applying that here, we have $(x+2)(x-2)(x^2+9)$ . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: $2x^2+10x-x-5$

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: $2x(x+5)-1(x+5)$

Now you can rewrite the equation as $(2x-1)(x+5)$ . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is $(x+2)(x-2)(x^2+9)(2x-1)(x+5)=0$ </u></h3>

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3 years ago