Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
I think the answer would be 4n
Answer:
m = 10/3
<em>(as a decimal: m = 3.333...)</em>
<em />
Step-by-step explanation:
5m - 8 = 2m + 2
5m - 8 = 2m + 2
- 2m - 2m <em>(make all "m" on one side to isolate variable)</em>
3m - 8 = 2
+ 8 + 8 <em>(get m entirely on 1 side)</em>
3m = 10
÷3 ÷3 <em>(divide by 3 to get 1m)</em>
m = 10/3
<em>(as a decimal: m = 3.333...)</em>
<em />
<em />
hope this helps!! have a lovely day :)
Answer:
Rewrite the equation as
3
b
+
4
c
=
a
.
3
b
+
4
c
=
a
Subtract
4
c
from both sides of the equation.
3
b
=
a
−
4
c
Divide each term by
3
and simplify.
Tap for more steps...
b
=
a
3
−
4
c
3
Step-by-step explanation:
