1884 i think the answer is-
Answer:
B
Step-by-step explanation:
To find the y-intercept, plug in x=0 in the original equation. (You want to find what y is when x=0)
2x + 3y = -12
2(0) + 3y = -12 (Plug in x=0)
3y = -12 (2*0=0, so you can ignore that part)
y = -4 (Divide both sides by 3)
This narrows down our choices to either A or B.
To find the x-intercept, plug in y=0 into the original equation. (You want to find what x is when y=0)
2x + 3y = -12
2x + 3(0) = -12 (Plug in y=0)
2x = -12 (3*0=0, so you can ignore that part)
x = -6 (Divide both sides by 2)
If our x intercept is -6 and our y intercept is -4, that makes our answer B.
I wrote answers in picture and I use Desmos app to solve this equations
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ =
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
It's 8! range is just the greatest value minus the lowest value
(=^_^=)