The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
x=−12/5
Step-by-step explanation:
2(1.5x−2)=−0.5(−4x−32)
Step 1: Simplify both sides of the equation.
−2(1.5x−2)=−0.5(−4x−32)
(−2)(1.5x)+(−2)(−2)=(−0.5)(−4x)+(−0.5)(−32)(Distribute)
−3x+4=2x+16
Step 2: Subtract 2x from both sides.
−3x+4−2x=2x+16−2x
−5x+4=16
Step 3: Subtract 4 from both sides.
−5x+4−4=16−4
−5x=12
Step 4: Divide both sides by -5.
−5x−5
=12/−5
x=−12/5
Answer:
The mean number of the children is 1.2
<em></em>
Step-by-step explanation:
Given
Children: 0, 1, 2, 1, 2
Required
Determine the Mean number
The mean of a set is calculated as follows;

Where x is the given set and n is the number of sets
In this case, n = 5 children
Hence;



<em>Hence, the mean number of the children is 1.2</em>
Answer:
The margin of error M.O.E = 2.5%
Step-by-step explanation:
Given that;
The sample size = 1500
The sample proportion
= 0.60
Confidencce interval = 0.95
The level of significance ∝ = 1 - C.I
= 1 - 0.95
= 0.05
The critical value:
(From the z tables)
The margin of error is calculated by using the formula:




M.O.E = 0.02479
M.O.E ≅ 0.025
The margin of error M.O.E = 2.5%
$3.42
Take the original price and multiply by 1.14
Explanation: 1.14 comes from the whole (1) of the orange juice at the time plus the percent (14% ---> .14).