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mestny [16]
3 years ago
9

Mary had 63 fliers to post around town last week she posted 1/3 of them this week she posted 2/3 of the remaining fliers how man

y fliers has she still not posted?
Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:down there

Step-by-step explanation:

Start with 60 fliers

post 1/4 of fliers so 60*.25=15

60-15=45 left

post 1/5 of remaining so 45*.20=9

45-9=36 left

Have a great day!

You might be interested in
Evaluate (3.5×10^13)-(1.4×10^12)/3×10^9
maw [93]

Answer:

11,200

Step-by-step explanation:

At first we use "BODMAS" rule.

Given,

(3.5×10^13)-(1.4×10^12)/3×10^9

So, we will break the brackets at first. With the help of excel, we can get the desired result. The following images will show you the step-by-step result.

Use "Number" instead of "general" in the excel sheet. You can use calculator too.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=14%20%5Cfrac%7B2%7D%7B7%7D%20-%205%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexFormula1" title="14 \fra
lubasha [3.4K]

To transform a mixed number to an improper fraction, we must multiply the denominator by the large number, and add the numerator.


So for 14\frac{2}{7}: (14*7)+2=100


But we also put this over the denominator in the mixed number, so we get: \frac{100}{7}.


Then we do the same for 5\frac{2}{3}:


(5*3)+2=\frac{17}{3}


Then we must find a common denominator. Let's use 21 (multiply 3 and 7):


\frac{100}{7} *\frac{3}{3}= \frac{300}{21}


\frac{17}{3}* \frac{7}{7} =\frac{119}{21}


Now that we have a common denominator, we can subtract across:


\frac{300}{21} -\frac{119}{21}= \frac{181}{21}


Since \frac{181}{21} cannot be reduced any further, we are going to leave this as our answer.


So the answer is \frac{181}{21}.

3 0
3 years ago
Help I need answers I don't know what to do I'm dumb it's due today
Alinara [238K]
1.<AFC
2.<AFD
3.<AFE
4.<AFB

#5, 6 and 7

m<BAE = 59

m<BAC  +  m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11

m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12

answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12

#8, 9 and 10

m<BAE = 130

m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20

m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35

answer

8.
m<BAC  = 50
9.
m<CAD  = 45
10.
m<DAE = 35 

4 0
3 years ago
3. What % of 100 is 13?
Sedbober [7]

Answer:

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 13 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 13 is 100%, so we can write it down as 13=100%.

4. We know, that x is 100% of the output value, so we can write it down as x=100%.

5. Now we have two simple equations:

1) 13=100%

2) x=100%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

13/x=100%/100%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 100% of 13

13/x=100/100

(13/x)*x=(100/100)*x       - we multiply both sides of the equation by x

13=1*x       - we divide both sides of the equation by (1) to get x

13/1=x

13=x

x=13

now we have:

100% of 13=13

Step-by-step explanation:

Have A Wonderful Day !!

5 0
3 years ago
Please help. Will give brainliest and 100 points!!!!
zubka84 [21]

Answer:

48cm^{2}

Step-by-step explanation:

The explanation is pinned.

plz give me Brainliest and 100 points.

7 0
3 years ago
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