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WITCHER [35]
3 years ago
13

c{2}{7} - 5 \frac{2}{3} " alt="14 \frac{2}{7} - 5 \frac{2}{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

To transform a mixed number to an improper fraction, we must multiply the denominator by the large number, and add the numerator.


So for 14\frac{2}{7}: (14*7)+2=100


But we also put this over the denominator in the mixed number, so we get: \frac{100}{7}.


Then we do the same for 5\frac{2}{3}:


(5*3)+2=\frac{17}{3}


Then we must find a common denominator. Let's use 21 (multiply 3 and 7):


\frac{100}{7} *\frac{3}{3}= \frac{300}{21}


\frac{17}{3}* \frac{7}{7} =\frac{119}{21}


Now that we have a common denominator, we can subtract across:


\frac{300}{21} -\frac{119}{21}= \frac{181}{21}


Since \frac{181}{21} cannot be reduced any further, we are going to leave this as our answer.


So the answer is \frac{181}{21}.

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Step-by-step explanation:

Equation at the end of step 1

(3x2 - 38x) + 24 = 0

STEP2:Trying to factor by splitting the middle term

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The first term is,  3x2  its coefficient is  3 .

The middle term is,  -38x  its coefficient is  -38 .

The last term, "the constant", is  +24 

Step-1 : Multiply the coefficient of the first term by the constant   3 • 24 = 72 

Step-2 : Find two factors of  72  whose sum equals the coefficient of the middle term, which is   -38 .

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Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -36  and  -2 

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Step-4 : Add up the first 2 terms, pulling out like factors :

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Step-5 : Add up the four terms of step 4 :

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             Which is the desired factorization

Equation at the end of step2:

(x - 12) • (3x - 2) = 0

STEP3:Theory - Roots of a product

 3.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

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 Add  12  to both sides of the equation : 

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