So here are the answers for the given questions above:
1. Based on the given values above, the correct answer would be option B. NEITHER ARITHMETIC NOR GEOMETRIC. Why? When we say arithmetic sequence, the values should have a common difference which remains constant all throughout the sequence, and this sequence does not qualify. On the other hand, a geometric sequence should have a common ratio, and these numbers do not have one.
2. The correct answer for this problem would be option C. <span>121,520.
Based on the given values above, the values have a common ratio of 1.1. So what we are going to do is just to multiply 1.1 each time and by 2016, we will get </span>121,520.
Hope these answers help.
96 with a remainder of 5.
Answer:
1/4
Step-by-step explanation:
the numerator is 12 because there are 12 possible outcomes. The numerator is 3 because there are 3 numbers in this set that are greater than 9. You get 3/12 which then simplifies to 1/4
Answer:
The answer is (h).
Step-by-step explanation:
When y = 2^x is shifted 4 units left, the x shifts 4 units to the left and x becomes (x+4). When the graph is shifted to units down, y has to be subtracted by 2.
The function becomes
y = 2^(x+4) -2.
Finally, you shift -2 to the same side as y.
This becomes
y+2 = 2^(x+4) which is (h)
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
