Answer:
Step-by-step explanation:
The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.
The x variable should be isolated on one side of the equation. The x variable is squared so before performing the square root property where we take the square root of both sides, we divide both sides by 2, then take the square root of both sides.
Dividing both sides by 2.
Taking the square root of both sides.
Jeremiah got $65 on birthday and spent some money on 3 video games and was left with $14.
He purchased 3 video games.
Let the cost one one video game be v.
The cost of each video game is same
So the cost of 3 video games is 3v.
Also he is left with $14 after paying for three games.
Hence
3v + 14 = 65
Subtracting 14 from both sides
3v + 14 -14 = 65-14
3v = 51
Dividing by 3 on both sides
v = 51/3
v = 17
Hence the cost of each video game is $17
Answer:
The three numbers are 341, 342, and 343
Step-by-step explanation:
We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1026. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 1026
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 1026
3X + 3 = 1026
3X + 3 - 3 = 1026 - 3
3X = 1023
3X/3 = 1023/3
X = 341
Which means that the first number is 341, the second number is 341 + 1 and the third number is 341 + 2. Therefore, three consecutive integers that add up to 1026 are 341, 342, and 343.
341 + 342 + 343 = 1026
We know our answer is correct because 341 + 342 + 343 equals 1026 as displayed above.
I think that it is attempt. If i am wrong, sorry.
Answer:
A
Step-by-step explanation:
Luis because the sample is taken from the population of all seventh graders.
