De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Ummm this confuses me a bit
Step 1
Collinear points are a set of three or more points that exist on the same straight line. Collinear points may exist on different planes but not on different lines.
Step 2
Graph the points; (-5,2),(0,6),(6,4)
Step 3
Conclude based on step 2
Since the points are not a straight line, we can conclude that the 3 points are not collinear.
293764 would be the answer to this question
Mentally
As they are numbers which you can do mental math with since they are whole numbers.
