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egoroff_w [7]
2 years ago
9

The the intensity I of light (in lumens) in a certain lake at a depth of x feet is given by log(1/12) = -0.00235x. What is the i

ntensity of the light (in lumens) at a depth of 20 feet? Round your answer to the nearest hundredth and label 1 your answer.​
Mathematics
1 answer:
ch4aika [34]2 years ago
4 0

Answer:

11.45 lumens

Step-by-step explanation:

We are given that

log(I/12)=-0.00235x

Where x=Depth

I=Intensity of light

We have to find the intensity of the light at a depth of 20 feet.

Substitute the value of x

log(I/12)=-0.00235\times 20

log(I/12)=-0.047

\frac{I}{12}=e^{-0.047}

I=12e^{-0.047}

I=11.45 Lumens

Hence, the intensity of the light (in lumens) at a depth of 20 feet=11.45 lumens

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Answer:

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Step-by-step explanation:

-0.65 + 0.45x = 5.4

First we will add 0.65 to each 'side' of the equation.

0.65 + (-0.65) + 0.45x = 0.65 + 5.4

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Input the numbers, and now the equation looks like this:

0 + 0.45x = 6.05

Remove the zero:

0.45x = 6.05

Divide each 'side' by 0.45.

0.45x ÷ 0.45 = 6.05 ÷ 0.45

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Input the numbers, and now the equation looks like this:

x = 13.444 ... repeating decimal

We can also write this as:

x = 13 4/9 in fraction form

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