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2 years ago

1) Una bicicleta circula en línea recta a una

Mathematics

1 answer:

erica [24]2 years ago

4 0

Answer:

the distance covered is 11.25 km

Step-by-step explanation:

Given that

The speed of the bicycle is 15 km/h

And, the time taken of the bicycle is 45 minutes

We need to determine the distance covered

As we know that

Speed = Distance ÷ Time

So, distance = Speed × time

= 15 km /h × 0.75 hours

= 11.25 km

The 0.75 hours come from

= 45 minutes ÷ 60 minutes

= 0.75 hours

Hence, the distance covered is 11.25 km

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Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$