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Whitepunk [10]
3 years ago
9

A store sells cans of paint for $8 each, and brushes for $12 each. If they sell 100 items, and

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

B.) 80 cans, 20 brushes

Step-by-step explanation:

Let the cans of paint be represented by variable <em>p</em> , and brushes by variable <em>b</em>

The first equation would be ; p + b = 100

p = 100 - b

The second equation would be;

8p + 12b = 880

Replace p in the equation by (100-b);

=8(100-b) + 12b =880

=800 - 8b +12b = 880

= subtract  800 from both sides to get;

4b = 880-800

4b = 80

divide both sides by 4 to solve for b;

b= 80/4

b = 20

If p + b = 100, then p+20 = 100

p = 100-20

p = 80

Therefore, they sold 80 cans of paint and 20 brushes

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