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3 years ago

How to tell if a relation is a function and give an example.

1 answer:

8 0

Ex: f: R ---> R
f(x)=2x+1
Definition: For every value of x , exists only one value of f(x)
f(1)=2*1+1, f(1)=2*1+1=3
f(2)=2*2+1=4+1=5
......
f(100)=2*100+1=200+1=201

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What do you do to both sides to<br> r? What is r? 3/8 r = 6 HELP ME

faust18 [17]

Answer:

r = 16

Step-by-step explanation:

$\frac{3}{8}r = 6 \\\\$

Multiply both sides by 8

$8*\frac{3}{8}r = 6*8\\\\3r = 48\\$

Divide both side by 3

$\frac{3}{3}r=\frac{48}{3}\\\\r = 16$

Multiply both side by (8/3)

$\frac{8}{3}*\frac{3}{8}r=6*\frac{8}{3}\\\\r = 2*8\\\\r = 16$

write an equation to represent the information in this problem. Jerel runs five days each week. on each of 4 days, he runs 2.3 km. if jerel runs a total of 14km, how many kilometers does he run on the fifth day?

Let x be the distance run on the fifth day

Total distance run on all the four days = 2.3 * 4 = 9.2 km

Required equation : x + 9.2 = 14

x = 14 - 9.2

x = 4.8 km

3 0

3 years ago

Math question quadratics

denpristay [2]

Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).

Step-by-step explanation:

To solve this question, we can represent variables for the length and width in two equations.

$2l + 2w = 160\\\\l * w= 1500$

To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:

$2l = 160 - 2w\\l = 80 - w$

$(80-w)*w=1500\\\\-w^2 + 80w - 1500 = 0\\\\w^2 - 80w + 1500 = 0$

Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:

$(w-50)(w-30) = 0$

This tells us that the width could be either 50 or 30.

Substitute 50 into one of the equations to find the length:

2 (l) + 100 = 160

l = 30.

The length and width are 50 and 30 meters (or 30 and 50 meters).

4 0

3 years ago

Read 2 more answers

The ratio of dogs to cats at the local pet store is 5 to 8. If there are 96 cats, how many dogs are there?

Vsevolod [243]

Answer:

dogs 5:8 cats

96/8 = 12

12 X 5 = 60

there are 60 dogs

7 0

3 years ago

A candy store has ten giant pieces of candy! Find the probability of each event. There are 4 gumdrops, 3 lolipops, 2 jellybeans,

AveGali [126]

Answer:

1. P = 9/90 = 1/10

2. P = 16/90 = 8/45

3. P = 10/90 = 1/9

4. P = 4/90 = 2/45

Step-by-step explanation:

Total no. of candy = 10

No. of Gumdrops = 4

No. of Lollipops = 3

No. of Jellybeans = 2

No. of Peppermint = 1

1. To find the probability that the child will pick a peppermint or jellybean, we will add the probabilities of both the candies.

P(Peppermint) = No. of Peppermint/Total no. of candy

= 1/10

P(Jellybean) = No. of Jellybean/Total no. of candy

= 2/10

P(Peppermint or Jellybean) = 1/10 + 2/10

P(Peppermint or Jellybean) = 3/10

Then, the child picks a lollipop. Note that after picking a peppermint or a jellybean, the number of candies left are 9. So,

P(Lollipop) = No. of Lollipops/Total no. of candy

P(Lollipop) = 3/9

To compute the probability that the child will pick a peppermint or a jellybean and then a lollipop,

P = P(Peppermint or Jellybean) x P(Lollipop)

= 3/10 x 3/9

P = 9/90 = 1/10

2. Probability that a child will pick a lollipop or peppermint:

P(Lollipop or Peppermint) = P(lollipop) + P(peppermint)

= 3/10 + 1/10

P(Lollipop or Peppermint) = 4/10

Then the child picks a gumdrop. Note that the number of candies remaining are 9. So,

P(Gumdrop) = 4/9

The probability that the child picks a lollipop or peppermint and then a gumdrop:

P = P(Lollipop or Peppermint) x P(Gumdrop)

= 4/10 x 4/9

P = 16/90 = 8/45

3. Probability that a child will pick a jellybean:

P(Jellybean) = No. of Jellybeans/Total no. of candy

P(Jellybean) = 2/10

Then the child picks a peppermint or a gumdrop. Note that one candy has been picked out so there are 9 candies left in total.

P(Peppermint or Gumdrop) = P(peppermint) + P(Gumdrop)

= 1/9 + 4/9

P(Peppermint or Gumdrop) = 5/9

The probability that a child picks a jellybean then a peppermint or a gumdrop is:

P = P(Jellybean) x P(Peppermint or Gumdrop)

= 2/10 x 5/9

P = 10/90 = 1/9

4. P(peppermint) = 1/10

Then the child picks a gumdrop. (remaining candies are 9)

P(Gumdrop) = 4/9

Probability that a child will pick a peppermint then a gumdrop:

P = P(peppermint) x P(gumdrop)

= 1/10 x 4/9

P = 4/90 = 2/45

5 0

3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY MATH ASAP PLEASE!!!!

WINSTONCH [101]

Answer:

x = 15

Step-by-step explanation:

Consider the right triangle on the left with hypotenuse h₁ , then

Using Pythagoras' identity

h₁² = x² + 9²

Consider the right triangle on the right with hypotenuse h₂ , then

h₂² = x² + 25²

Now consider the large right triangle with legs h₁ and h₂ , then

h₁² + h₂² = (9 + 25)² , substitute values

x² + 9² + x² + 25² = 34² , that is

2x² + 81 + 625 = 1156

2x² + 706 = 1156 ( subtract 706 from both sides )

2x² = 450 ( divide both sides by 2 )

x² = 225 ( take the square root of both sides )

x = $\sqrt{225}$ = 15

5 0

3 years ago