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Oksanka [162]
3 years ago
14

Parallelograms ABCD and EFGH are similar figures because angles A, B, C, and D are congruent to angles E, F, G, and H, respectiv

ely. If DA equals 8 units, AB equals 11 units, and HE equals 32 units, what does EF equal?

Mathematics
2 answers:
Ganezh [65]3 years ago
8 0
If I’m reading this correctly, the correct answer would be 11, because AB is congruent to EF, and they gave you AB
rusak2 [61]3 years ago
4 0

Answer:

It is 44

Step-by-step explanation:

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Find the solution to the system of equations-2 + 2y = -4 3x + 3y = -18
AfilCa [17]

Answer:

\boxed{x = -2~~and~~ y = -4}

Step-by-step explanation:

-2x + 2y = -4 (times 3) -6x + 6y = -12

3x + 3y = -18 (times 2) 6x + 6y = -36

.

-6x + 6y = -12

<u>6x + 6y = -36 </u>+

12y = -48

y = \frac{-48}{12}

y = -4

.

Substitute the value of y to the one of equations

-2x + 2(-4) = -4

-2x - 8 = -4

-2x = -4 + 8

-2x = 4

x = \frac{4}{-2}

x = -2

4 0
3 years ago
Read 2 more answers
Lines DE and AB intersect at point C.
cluponka [151]

Answer:

25

Step-by-step explanation:

2x+2+5x+3=180

7x=175

x=24

6 0
2 years ago
Of all the numbers whose difference is 10, find the two that have the minimum product
Nostrana [21]

Answer: -9

Step-by-step explanation:  You might think that the smallest two numbers are 11 and 1 but there are negative numbers. 1 - (-9) is equal to 10. 1 x (-9) is -9.

7 0
2 years ago
A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p
Kay [80]

Answer:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by V= 10 +t

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of \frac{A}{10+t}

So then we can reorder the differential equation like this:

\frac{dA}{dt} +\frac{A}{10+t} =8

We find the solution using the integration factor:

\mu = -\int \frac{1}{10+t} dt = -ln(10+t)

And then the solution would be given by:

A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})

And if we simplify this we got:

A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)

And after do the integral we got:

A= \frac{c}{10+t} +4 (10 +t)

And using the initial condition t=0 A= 20 we have this:

20 = \frac{c}{10} +40

c= -200

So then we have this function for the solution of A:

A= \frac{-200}{10+t} +4 (10 +t)

And now replacinf t= 40 we got:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

8 0
3 years ago
Let g(x)=2x and h(x)=x^2+4 <br><br> (g o h)(0)
sweet [91]
Answer would be 0 because whatever you get when you plug in g&h in the equation you have to multiply that by 0. And a number multiplied by 0 is always 0.
Hope this helped. Have a great day!
4 0
4 years ago
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