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Elena L [17]
3 years ago
13

A cube has a lateral area of 9 square centimeters. What is the length of each edge of the cube?

Mathematics
2 answers:
worty [1.4K]3 years ago
4 0

the answe on edg is 1.5

miss Akunina [59]3 years ago
3 0
Check the picture below, that'd be a cube, all equal sides so 6 squares really, its lateral or sides section are just the squares at front, back, left, right.

if say, one side is hmm "s" units long, the area of just one square is s*s or s², and the area of those four lateral squares will just be 4(s²), or 4s² then.

now, we know the lateral area is 9 cm², namely 9 = 4s², thus

\bf 9=4s^2\implies \cfrac{9}{4}=s^2\implies \sqrt{\cfrac{9}{4}}=s\implies \cfrac{\sqrt{9}}{\sqrt{4}}=s\implies \cfrac{3}{2}=s

and surely you know how much that is.

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Yuliya22 [10]

Check your answer. Is $15.75 a reasonable amount of interest? If Caroline had invested the $900 for a full year at 2% interest, the amount of interest would have been $18. Yes, $15.75 is reasonable.

Step-by-step explanation:

8 0
3 years ago
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Pls help will give brainly
mars1129 [50]

Answer:

-8

Step-by-step explanation:

Since x = -18, we use the top formula

f(-18) = (x-6)/3

        = (-18-6)/3

        = -24/3

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HELP ASAP!!!! While riding on a carousel, Angela travels a distance of 65 meters every 15 seconds. What is her speed in kilomete
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Lucinda has a coin collection. she sold 12 coins to a friend and bought 7 new coins. she then had 39 coins. How many did she hav
erik [133]

Answer: 44

Step-by-step explanation:The way to calculate the number of coins that she had originally is to look at the difference in coins that changed hands. She sold 12 coins, but only bought 7 new ones. 12-7=5. Lucinda now has 5 coins less than what she started out with. So, she has 39 now, and then add 5 and the answer is 44 coins.

4 0
3 years ago
Which of the following equations are dimensionally consistent?
pishuonlain [190]

Answer:

A. x = 1/2at²

Step-by-step explanation:

Among the equations, the equation that is dimensionally consistent is x=1/2at² where;

x is the distance in meters (dimension is length (L))

a is the acceleration in m/s² (dimension is L/T²)

t is the time in seconds (s) (dimension of time is T)

Substituting the dimensions into the formula to check if we are going to arrive at the dimension for distance;

1/2at² = 1/2(L/T²)T²

= 1/2× L/T² × T²

= 1/2 × L

Since L which is the resulting dimension is the dimension for distance (x), this means that the equation x = 1/2at² is dimensionally consistent.

4 0
3 years ago
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