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Nitella [24]
3 years ago
12

Pleeaase help.......

Mathematics
2 answers:
Ymorist [56]3 years ago
8 0

Answer:

Options B and D

Step-by-step explanation:

Let's solve each equation:

x-3x=-2x+4

-2x=-2x+4

0=4

No solutions, so A is wrong

x-1/3(3x)=0

x-(3x/3)=0

x-x=0

0=0

Infinitely many solutions, so B is correct

1/3x-3=4+2x

1/3x=7+2x

-5/3x=7

x=-21/5

One solution, so C is incorrect

3x+2-1/3(3x)=2+2x

3x+2-(3x/3)=2+2x

3x+2-x=2+2x

2x+2=2+2x

2x=2x

0=0

Infinitely many solutions, so D is correct

x-1/3x+2=0

2/3x+2=0

2/3x=-2

x=3

One solution, so E is incorrect

As you can see, when both sides of the equations are equal to each other such as 0=0 and x=x, you'll always have infinitely many solutions. Therefore, options B and D are correct

madreJ [45]3 years ago
7 0

Answer:

The 1st, 3rd and 4th

Step-by-step explanation:

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<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable  c  in equation [1]

<span><span>  [1] 2a + (-a +2?-5) = -10 </span><span>  [1] a = -5 </span></span>

// Plug this in for variable  c  in equation [2]

<span><span>  [2] - (-? +2b-5) + b = 15 </span><span>  [2] - b = 10 </span></span>

// Solve equation [2] for the variable  ?  
 

<span> [2] ? = b + 10 </span>

// Plug this in for variable  ?  in equation [1]

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3 0
3 years ago
Help please, tank u :)
elena-s [515]

Answer:

16 ft

Step-by-step explanation:

Let the width of the rectangle be x ft

Therefore, length = (x + 2) ft

Area of the rectangle = 15 square ft

x(x + 2) = 15 \\  \\  {x}^{2}  + 2x = 15 \\  \\  {x}^{2}  + 2x - 15 = 0 \\  \\  {x}^{2}  + 5x - 3x - 15 = 0 \\  \\ x(x + 5) - 3(x + 5) = 0 \\  \\ (x + 5)(x - 3) = 0 \\  \\ x + 5 = 0 \: or \:  \: x - 3 = 0 \\  \\ x =  - 5  \:  \: or \:  \: x = 3 \\  \\  \because \: x \: can \: not \: be \:  - ve \\  \\  \therefore \: x = 3 \\   \\  \implies \: x + 2 = 3 + 2 = 5 \\  \\ perimeter \: of \: rectngle  \\ = 2(5 + 3)  \\  = 2 \times 5 \\  = 16 \: ft

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3 years ago
0.4(x-0.45)=9.2 PLZZZZZ HELP!!!!!!!
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Answer:

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Step-by-step explanation:

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