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Taya2010 [7]
1 year ago
7

the probability of serena serving an ace in tennis is 0.15, and the probability that she double faults is 0.25. (note that you c

annot both ace and double fault at the same time.) what is the probability that serena does not serve an ace or a double fault?
Mathematics
1 answer:
harkovskaia [24]1 year ago
6 0

The probability that Serena does not serve an ace or a double fault is 0.6, when the probability of Serena serving an ace in tennis is 0.15, and the probability that she double faults is 0.25.

<h3>Define probability.</h3>

The formula of the favorable outcome over the total outcomes is used to describe probability. The likelihood of flipping a coin heads is one example. Given that there is only one head and two total sides, 50% of the time, a head will land up-side-down.

Given,

Serve tennis probability = 0.15

No ace probability = 1-0.15

No ace probability = 0.85

Double fault probability = 0.25

No double fault probability = 1-0.25 = 0.75

No double fault probability = 0.75

The probability of not receiving an Ace or Double Fault: is

= 0.75 ×0.85

= 0.6.

The probability that Serena does not serve an ace or a double fault is 0.6.

To learn more about probability, visit:

brainly.com/question/11234923

#SPJ4

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Answer: d and b i think

Step-by-step explanation:

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Find the measure of 0. (To the nearest tenth)<br> A) 28.8<br> B) 33.4<br> C) 61.2<br> D) 63.4
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Step-by-step explanation:

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4 0
2 years ago
Match each time with a time in the box.
BigorU [14]
If you would like to match each time with a time above, you can do this using the following steps:

a 3h 18m 7s = 11887s<span>
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b <span> 8300min = approximately 5 days 18 hours
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7 0
3 years ago
Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ &lt; 98.6, and level of significance α = 0.05. 98 99.6 97.8
andrezito [222]

Answer:

The t-score is -1.8432    

Step-by-step explanation:

We are given the following in the question:  

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1964.4}{20} = 98.22

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s = \sqrt{\dfrac{16.152}{49}} = 0.922

Population mean, μ = 98.6

Sample mean, \bar{x} = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

H_{0}: \mu = 98.6\\H_A: \mu < 98.6

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432

The t-score is -1.8432    

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Tom [10]

Answer:

I think that the answer is -12/47

3 0
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