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Taya2010 [7]
1 year ago
7

the probability of serena serving an ace in tennis is 0.15, and the probability that she double faults is 0.25. (note that you c

annot both ace and double fault at the same time.) what is the probability that serena does not serve an ace or a double fault?
Mathematics
1 answer:
harkovskaia [24]1 year ago
6 0

The probability that Serena does not serve an ace or a double fault is 0.6, when the probability of Serena serving an ace in tennis is 0.15, and the probability that she double faults is 0.25.

<h3>Define probability.</h3>

The formula of the favorable outcome over the total outcomes is used to describe probability. The likelihood of flipping a coin heads is one example. Given that there is only one head and two total sides, 50% of the time, a head will land up-side-down.

Given,

Serve tennis probability = 0.15

No ace probability = 1-0.15

No ace probability = 0.85

Double fault probability = 0.25

No double fault probability = 1-0.25 = 0.75

No double fault probability = 0.75

The probability of not receiving an Ace or Double Fault: is

= 0.75 ×0.85

= 0.6.

The probability that Serena does not serve an ace or a double fault is 0.6.

To learn more about probability, visit:

brainly.com/question/11234923

#SPJ4

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If each tricycle has 3 wheels and 1 seat, the ratio of seats:wheels is 1:3.
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3 years ago
Solving a system of equation <br> x+5y=15 <br> -3x+2y=6
Colt1911 [192]

Answer:

(0,3)

y=3

x=0

Step-by-step explanation:

x+5y=15

-3x+2y=6

solve the equation

x=15-5y

-3x+2y=6

substitute the value of x into an equation

-3(15-5y)+2y=6

distribute

-45-15y+2y=6

add 15 to 2

-45-17y=6

add 45 from both sides

17y=51

divide both sides by 17

y=3

substitute the value of y into an equation

x=15-5•3

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subtract

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6 0
2 years ago
1. Iris has two ribbons. The first ribbon is 11.7 in. long. The second ribbon is 5.25 in. long. She wants to cut them so that th
lisov135 [29]
The estimated lengths are 12in. and 5 in. This would be an estimated difference of 7in.


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3 years ago
Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

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Well what i got was 79.3 by finding the average by adding it all together then divided it by how many numbers
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