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Furkat [3]
3 years ago
14

Discuss different types of data?[At the language of computer information and technology system]

Computers and Technology
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

n computer science and computer programming, a data type or simply type is an attribute of data which tells the compiler or interpreter how the programmer intends to use the data. Most programming languages support basic data types of integernumbers (of varying sizes), floating-point numbers (which approximate real numbers), characters and Booleans. A data type constrains the values that an expression, such as a variable or a function, might take. This data type defines the operations that can be done on the data, the meaning of the data, and the way values of that type can be stored. A data type provides a set of values from which an expression(i.e. variable, function, etc.) may take its values.[1][2]

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In the NumPy function, the data preparation technique that is used to help machine learning algorithms is called _________.
KonstantinChe [14]

In the NumPy function, the data preparation technique that is used to help machine learning algorithms is called the reshape technique or function

For better understanding, let us explain what the reshape function means

  • The numpy package helps to give the right tools for scientific and mathematical computations in python . it includes functions that cam be used to perform common linear algebra operations, fast Fourier transforms, and statistics The reshape function simply alter or change the row and column arrangement of data in numpy function and it is said to just give new shape to an array without the altering of its data.

from the above, we can therefore say that the answer In the NumPy function, the data preparation technique that is used to help machine learning algorithms is called the reshape technique or function is correct

learn more about reshape function  from:

brainly.com/question/24728884

3 0
2 years ago
Complete the steps to evaluate the following
kirill115 [55]

Answer:

log base 3a= -0.631.log a/3 base 3

Now, -log m= log 1/m

hence,

log base 3a= 0.631.log 3/a base 3

log base 3a/log 3/a base 3 =0.631

log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)

log base 3 3=0.631

Hence, answer is log base 3 3=0.631

Explanation:

Please check the answer section.

3 0
3 years ago
Read 2 more answers
What approach to dealing with deadlock does the wait-for graphs implement (prevention/avoidance/detection/ recovery)?
V125BC [204]
"detection" by checking for possible cycles or knots.
3 0
4 years ago
The _________ operator returns the distance in bytes, of a label from the beginning of its enclosing segment, added to the segme
DanielleElmas [232]

Answer:

C. Offset.

Explanation:

An offset operator can be defined as an integer that typically illustrates or represents the distance in bytes, ranging from the beginning of an object to the given point (segment) of the same object within the same data structure or array. Also, the distance in an offset operator is only valid when all the elements present in the object are having the same size, which is mainly measured in bytes.

Hence, the offset operator returns the distance in bytes, of a label from the beginning of its enclosing segment, added to the segment register.

For instance, assuming the object Z is an array of characters or data structure containing the following elements "efghij" the fifth element containing the character "i" is said to have an offset of four (4) from the beginning (start) of Z.

8 0
3 years ago
Suppose that the splits at every level of quicksort are in the proportion 1 − α to α where 0 < α ≤ 1/2 is a constant. Show th
Lady_Fox [76]

Answer:

Explanation:

The minimum depth occurs for the path that always takes the smaller portion of the

split, i.e., the nodes that takes α proportion of work from the parent node. The first

node in the path(after the root) gets α proportion of the work(the size of data

processed by this node is αn), the second one get (2)

so on. The recursion bottoms

out when the size of data becomes 1. Assume the recursion ends at level h, we have

(ℎ) = 1

h = log 1/ = lg(1/)/ lg = − lg / lg

Maximum depth m is similar with minimum depth

(1 − )() = 1

m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )

4 0
4 years ago
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